Question

A cardiac monitor is used to measure the heart rate of a patient after surgery. It compiles the number of heartbeats after t minutes. When the data in the table are graphed, the slope of the tangent line represents the heart rate in beats per minute 36 38 40 42 Heartbeats 2517 2657 2797 2937 3075 The monitor estimates this value by calculating the slope of a secant ine. Use the data to estimate the patient's heart rate after 42 minutes using the secant line between the points with the given values of t. (Round your answers to one decimal place) (a) - 36 and t = 42 (b) t = 38 and 42 (c) t = 40 and t = 42 (d) - 42 and t = 44

Answer 1

Hello Student! solm let Heartbeats be be H H₂- Hi ( Heart Rate) Slope of secant line ta-ti a t=36 and t = 42 ti 36 ty = 42. » H, 2517 & H₂ = 2937 70 slope 2937-2517 42-36 420 6 (b. ti =38 t₂ = 42 H, = 2657 H₂ 2937 467 70 11 Il Slope 2937 - 2657 42-36 280 4 2797 ti= 40 tz - = 42 Slope = Hi- H₂ 2937 140 = 70 2937 - 2797 42-40 2 ti 42 A, 2937 H₂ = 3075 tz = 44 ) 138 = 69 - Slope 3075- 2937 44 - 42