Homework Answers
only one cycle due to the limiting reactant
ratio is 3:2 so there is only a formation of 2 mol of product
I2 left over = 6-1 = 5 molecules I2 left
Since Cl2 is limiting reactant, expect no leftover of Cl2
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For a gas reactor containing 6 I_2 molecules and 3 CI_2 molecules, answer the questions that...
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2. Write the balanced equation for the formation of ammonia from nitrogen gas and hydrogen gas....
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An aqueous solution containing 7.30 g of lead(II) nitrate is added to an aqueous solution containing...
An aqueous solution containing 7.30 g of lead(II) nitrate is
added to an aqueous solution containing 6.87 g of potassium
chloride. Enter the balanced chemical equation for this reaction.
Be sure to include all physical states.
An aqueous solution containing 7.30 g of lead(lI) nitrate is added to an aqueous solution containing 6.87 g of potassium chloride. Enter the balanced chemical equation for this reaction. Be sure to include all physical states. Tip: If you need to clear your work...
An aqueous solution containing 8.16 g of lead(II) nitrate is added to an aqueous solution containing...
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An aqueous solution containing 5.69 g of lead(II) nitrate is added to an aqueous solution containing...
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An aqueous solution containing 5.65 g of lead(II) nitrate is added to an aqueous solution containing 6.26 g of potassium chloride. Enter the balanced chemical equation for this reaction. Be sure to include all physical states. balanced chemical equation: What is the limiting reactant? O potassium chloride lead(II) nitrate The percent yield for the reaction is 81.4%. How many grams of the precipitate are formed? precipitate formed: How many grams of the excess reactant remain? excess reactant remaining:
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Attempt 2 - An aqueous solution containing 8.03 g of lead(II) nitrate is added to an...
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An aqueous solution containing 5.22 g of lead(II) nitrate is added to an aqueous solution containing...
An aqueous solution containing 5.22 g of lead(II) nitrate is added to an aqueous solution containing 5.19 g of potassium chloride to generate solid lead(II) chloride and potassium nitrate. Write the balanced chemical equation for this reaction. Be sure to include all physical states. _______ Tip: If you need to dear your work and reset the equation, click the button that looks like two arrows. What is the limiting reactant? lead(II) nitrate potassium chloride The percent yield for the reaction...
1. Problem Set 4 Chem 141 When hydrogen sulfide (H.S. MM - 34,08 g/mol) gas is...
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2. Write the balanced equation for the formation of ammonia from nitrogen gas and hydrogen gas. Balanced Equation: Given 6 molecules of nitrogen and 12 molecules of hydrogen, make a drawing that represents the reaction container before and after the reaction Before After Now construct a Before-Change-After Table for this reactantur: Bal. Equation: Na - Ha Ha Before: Change: After: Use your representations above to answer the following questions about the reaction a. How many molecules of ammonia can be...
An aqueous solution containing 7.30 g of lead(II) nitrate is
added to an aqueous solution containing 6.87 g of potassium
chloride. Enter the balanced chemical equation for this reaction.
Be sure to include all physical states.
An aqueous solution containing 7.30 g of lead(lI) nitrate is added to an aqueous solution containing 6.87 g of potassium chloride. Enter the balanced chemical equation for this reaction. Be sure to include all physical states. Tip: If you need to clear your work...
An aqueous solution containing 8.16 g of lead(II) nitrate is added to an aqueous solution containing 6.57 g of potassium chloride. Enter the balanced chemical equation for this reaction. Be sure to include all physical states. balanced chemical equation: Pb(NO3)2(aq) + 2 KCl(aq) + PbCl,(s) + 2 KNO3(aq) What is the limiting reactant? O potassium chloride lead(II) nitrate The percent yield for the reaction is 91.6%. How many grams of precipitate is recovered? precipitate recovered: How many grams of the...
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