Question

Question 11 View Policies Current Attempt in Progress Use the t-distribution to find a confidence interval for a mean given the relevant sample results. Give the best point estimate for the margin of error, and the confidence interval. Assume the results come from a random sample from a population that is approximately normally distributed. A 90% confidence interval for using the sample results T = 3.2.5 = 0.2, and n = 100 Round your answer for the point estimate to one decimal place, and your answers for the margin of error and the confidence interval to two decimal places. point estimate - i margin of error - i The 90% confidence interval is i

Answer 1

The statistical software output for this problem is:

One sample T summary confidence interval: u: Nean of population 90% confidence interval results: Mean Sample Mean Std. Err. DF L. Limit U. Limit 3.2 0.02 99 3.1667922 3.2332078

From above output:

Point estimate = 3.2

Margin of error = (3.233 - 3.167)/2 = 0.03

90% confidence interval: 3.17 to 3.23