The null and alternative hypotheses for this case are,
H0 : μ = 15
Ha : μ > 15
sample size (n) = 24
=> Degrees of freedom = 24 - 1 = 23
Since, this is right-tailed test, t-critical value at significance level of 0.05 with 23 degrees of freedom is, t* = 1.714
Excel Command : =TINV(0.10, 23) = 1.714
Answer : t* = 1.714
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