Question

or Design Layout References Mailings Review View Help Tell me what you want to do files from the Internet can contain vituses. Unless you need to edit, it's safer to stay in Protected View Enable Editing Plane Suppose that the block were made to move along the inclined plane upward with uniform velocity by an applied force (F.) parallel to the incline. Derive an equation for the coefficient of kinetic friction for this case in terms of (A free body diagram may help.) a) The applied force (Frp). b) The Weight of the block, c) The angle of the inclined plane . Pulling Force Normal Force N Mass mo Frictional Forces Mass Weight Wolock www Pulling Force F-Weight W = (1 + 0.05) xg Determine how the normal force relates to the part of weight of the box block and angle e Determine how Pulling Force Frelates to Frictional Forceſ, the part of the weight of the box Ilock and angle e en- e to search

Answer 1

wsino wsino HE wcoso fap fap=mg W tm inclined) Met force =0 0 perpendicular to the plane N-wcoso IN E wcoso ool M= Normal force h (i) we know that the frictional force = MN f = uncoso ab for uniform motion along inclined fnet to Fap - wsino-f=0 fahit tap-weine uno = tap - wsing fap-wsind M = coeficient of friction = M = Tapi 6 - Min M = Wcoso.

(1) along the inclined Fap - Wsine-fao I Fap = (ft wing) to move the block uniformly, net force along the inclined plane must be zero.]