Question

Question: Let's assume that we have an LED rated at 25 mA, 3.3V DC that we are connecting to a 9V battery. In order to prevent the bulb from burning out and emitting light as brightly as possible, we can add: None of the answers are correct (except this one!) a 270-ohm resistor O a 1-Mohm resistor O don't add anything, it should work fine a 1-kohm resistor Previous Page Next Page Page 8 of 11

Answer 1

Here the supply voltage = que qu (power supply) - 3.3(LED): 5.70. so. Now. 5.70. Potential has to be taken by an resistor. V=IR s 5.7= 25x10 3xR - XR = 2282 so adjusting 5% I ears. we can add : Ta 270-0hm veristen