2. Write the cosine based phasors in complex number form (a + b) for the following...
Part E - Use phasors to subtract one sinusoid from another sinusoid Suppose you want to find the difference of two sinusoidal currents, given as follows: ¿1(t) = 1; cos(wt+$1) and iz(t) = 12 cos(wt+$2). If you stay in the time domain, you will have to use trigonometric identities to perform the subtraction. But if you transform to the frequency domain, you can simply subtract the phasors I1 and 12 as complex numbers using y calculator. Make sure that all...
#4: Complete the following: a) Convert to phasor form: A = 10 cos (s. 10 + /4) b) Convert to phasor form: B(1,1) = 32 sin (8710'+2.r --30°) ay c) Convert the phasor A. = 35337/4 to the exact time domain form A () = A, sin (wt + o), with w = 2 10% rad/sec. Since it is not defined, you must use the baseline assumption, A, = Re 4 d) Convert from phasor to a single cosine or...
10 in Cartesian coordinates. (a) Write the complex number (b) Write the complex number (c) What is the phasor representation of the signal 4. (2 + j4)(3-J)in Polar coordinates i = 4 sin(10t + 10%) ǐn polar coordinates? (d) What is the time domain sinusoidal represenation of the phasor if the frequency of the signal is o- 20 rad/s? I=j(5-j12) if (e) What is the time domain sinusoidal represenation of the phasor the frequency of the signal is ω-10 rad/s?...
(a) Write the relationship between the instantaneous time voltage i(t) = 1, cos(wt+p) and its phasor transform I. Write phasor transforms of the following voltages and currents. All answers should be in the form of AZB where A is a positive number A 20 and B is given in degrees over the range of -180° <B S 180°. Make sure that you include the units. Show all work to receive partial credit. (6) v(t) = VŽ cos(7t + 1/4 -...
1. (40 points) Write down the phasor representation for each of the following signals a. (5 pts) x, () 12cos(21) b. pts) x(1)-20cos(3t+45) c. (5 pts)x,(t)-10sin(21 + 300) d. (5 pts) x,(t)-35cos(20+22 sinQ2 +45") e. (10 pts) )- d 135cos(21)+22 sin(2i+4')leas ao express the result in the time domain. f (10 pts) ,)-[B5cos(21)+22sin(2r +45°ydr. Please also express the result in the time domain. Notes: Phasors are ideal for steady-state analysis of sinusoidal signals at a fixed frequency, so we cannot...
1. (40 points) Write down the phasor representation for each of the following signals a. (5 pts) x, () 12cos(21) b. pts) x(1)-20cos(3t+45) c. (5 pts)x,(t)-10sin(21 + 300) d. (5 pts) x,(t)-35cos(20+22 sinQ2 +45") e. (10 pts) )- d 135cos(21)+22 sin(2i+4')leas ao express the result in the time domain. f (10 pts) ,)-[B5cos(21)+22sin(2r +45°ydr. Please also express the result in the time domain. Notes: Phasors are ideal for steady-state analysis of sinusoidal signals at a fixed frequency, so we cannot...
PROBLEMS Given in5 cos (400 120%) A, determine the period of he current and the frequency in Hertz. s galculate the current in the resistor in Fig. P8.S if the voltage input is (a) (0)-10 cos (3771 +180°%) V (b) 00 12 sin (377t +45) V Give the answers in both the time and frequency domains 8.2/Determine the relative phase relationship of the two waves ana M(010 cos (377t- 30) v n)10 cos (3771 +90*) v e.9) Given the following...
Problem 3: Evaluate the following expression using phasor identities 102-30° +(3-14) (2+14)(3-15)* Problem 4: Simplify 5cos(or +539)+ V2 cos(@r+45) using phasors (much easier than using the cosine addition formula three times!) Problem 5: Express the following sinusoids in sin form. Which sinusoid leads? By how much? V = -10cos(or +509) v, = 12 sin(01-10)
Name 7. For the following circuit: a. b. c. d. Find the (steady-state) mesh currents as functions of time. Find the complex What is the PFA for the voltage source? As seen by the voltage source, is capacitive? power supplied by the voltage source. the circuit pri marily ind uctive or primarily 10 uF 0.25 H 50 0 50 cos(377t + 459) V sin(377t) A
3. Write the following in positive cosine form: a) 6*cos(2t 1E6*t-18°) b) 3*sin(2t 1E3 t+184°) c) -2*cos(2Tt 12E4*t+12) d) -7*sin(2Tt 10E3 t-270°)