Question

CECS Project 1 RPS (Rock-Paper-Scissors) Game Use python This project asks you to practice . creating a new python file using pycharm . doing text- based input and output building your own algorithm using branching and loop Your program should operate as follows It must let the user choose from among three options of rock, paper, and scissors It shall play an honest game of RPS Display the choice the user made . If the user input is not one of the allowed, then ask for the user to re-enter (input validation!!) Print out its choice of R/P/S Display who won the round, or tie Offer an option to continue until user wants to quit the game. Your program must be well commented

Answer 1

//code

from random import randint

options = ["Rock", "Paper", "Scissors"]

#choosing options for computer randomly

computer_choice = options[randint(0,2)]

#set player to False

player = False

#we keep on playing till player doesn't want to play

while player == False:

#set player to True

#Taking input from the user and displaying it only in the correct cases

player = input("Rock, Paper, Scissors? ")

if player == "Rock" or player == "Paper" or player == "Scissors":

print("You entered: ", player)

#tie in case of same generated for computer

if player == computer_choice:

print("Tie!")

elif player == "Rock":

if computer_choice == "Paper":

print("You lose!", computer_choice, "covers", player)

else:

print("You win!", player, "smashes", computer_choice)

  

elif player == "Paper":

if computer_choice == "Scissors":

print("You lose!", computer_choice, "cut", player)

else:

print("You win!", player, "covers", computer_choice)

elif player == "Scissors":

if computer_choice == "Rock":

print("You lose...", computer_choice, "smashes", player)

else:

print("You win!", player, "cut", computer_choice)

  

else:

print("That's not a valid play. Check your spelling!")

player = False

continue

#player was set to True, but we want it to be False so the loop continues

choice = input("Do you want to continue playing Y/N? ")

if choice.lower() == 'y':

player = False

else:

player = True

#generating computer's choice for the next game

computer_choice = options[randint(0,2)]

//output

Explanation:

We have created a list of all three options and every time we are using python's random number generation library for generating a random integer between 0 to 2. We will use this integer as the index of our list and give the value at that particular index as the computer's choice. We will then compare computer's randomly generated choice with user's choice for different cases.