JUL &coursejd_40296_1&new_attempt=1&content_ide_1144581.18 Question Completion Status: 35.0 mL of 0.10M propanoic acid CH3CH2COOH (K 1.3 x 10")...
i need help on both LUIUS. Question Completion Status: QUESTION 21 A 35.0 mL sample of 0.180 M benzoic acid is titrated with a 0.180 M NaOH solution. What is the pH at the equivalence point? The Ka of benzoic acid is 6.3 10-5 11.20 9.80 4.20 08.58 7.00 QUESTION 22 A 25.0-ml sample of 0.150 M hydrocyanic acid (HCN) is titrated with a 0.150 M NaOH solution. What is the pH after 13 ml NaOH has been added? The...
Nicole measured the pH of a 0.100 M solution of propanoic acid, CH3CH2COOH, a weak organic acid at equilibrium and found it to be 2.931 at 25C. Calculate the Ka of propanoic acid. Her lab instructor mentions that the half equivalence method is better for determining pKa. What is the half-equivalence point and why is this method better at determining pKa? What is the pH after 20.0 mL of 0.0750 M NaOH is added to 30.0 mL of the 0.100...
1. 50.00 mL of 0.1000 M propanoic acid (CH3CH2COOH – Ka = 1.34 X 10-5) is titrated with 0.2000 M KOH. Calculate the pH at the following points in the titration: 1) Initial pH – no KOH has been added. 2) 5.00 mL of KOH has been added. 3) 12.50 mL of KOH has been added. 4) At the equivalence point. (Calculate the volume of KOH to reach the equivalence point & identify a good indicator.) 5) Provide a sketch...
thanks Question 23 (2.5 points) Saved A 25.00-ml sample of propanoic acid, CH3CH2COOH, of unknown concentration was titrated with 0.143 M KOH. The equivalence point was reached when 35.28 mL of base had been added. What is the concentration of the propanoate ion at the equivalence point? 0.143 M 0.0837 M 0.202 M 0.128 M 0.147 M نعمه
A buffer solution was prepared that was 0.20M in propanoic acid (C2H5COOH; Kz = 1.3 x 10^-5) and 0.40 in sodium propanoate. What is the pH of 150.0 ml of this buffer after 0.003 mol of hydrochloric acid is added to it? A. 4.51 B. 5.13 C. 5.25 D. 4.65 E. 5.19
Propanoic acid (HC3H8O2) has a Ka of 1.3*10^-5. if you are titrating a 25.00 mL sample of 0.355 M propanoic acid with 0.525 M NaOH, calculate the pH before the titration has started.
Question 2 15 P Weak Acid Titration Calculations. A 25.0 mL aliquot of 0.50 M propanoic acid (CH3CH2O2H) is placed in a 250 mL Erlenmeyer flask and titrated with a standardized solution of 0.25 M NaOH. The pKof propanoic acid is 4.88. Calculate the pH of the solution after the addition of the following volumes of acid. Neglect activity. (15 points) a) 0.00 mL of NaOH added: 2.59 b) 50.00 mL of NaOH added: 8.49 c) 75.00 mL of NaOH...
A 25.0 mL sample of 0.100 M propanoic acid (HC3H5O2, Ka = 1.3 ✕ 10-5) is titrated with 0.100 M KOH solution. Calculate the pH after the addition of the following amounts of KOH. 0.0 mL 4.0 mL 8.0 mL 12.5 mL 20.0 mL 24.0 mL 24.5 mL 24.9 mL 25.0 mL 25.1 mL 26.0 mL 28.0 mL 30.0 mL
Preparing Buffer Solutions: Calculating the Number of Grams of Conjugate Base Needed Use the table of K values given with this problem to choose the best weak acid to start from for making a buffer that holds the pH of the solution at 8.50. Make your selection so that you maximize the capacity of the buffer. Weak Acid K 1.8 X 10-5 6.5 X 10-5 1.5 X 10-5 You select a 800.0 ml volumetric flask to which you add 8.00...
Propanoic acid (abbreviated as HPro K, - 13 x 10) is produced naturally by a bacterium that is also responsible for forming the holes in Swiss cheese. An extract of 45.0 mL of HPro from some cheese had a propanoic acid molarity of 0.0150 M. This was titrated with 19.85 mL of 0.034 M NaOH. What was the pH of the resulting solution? OA 9.11 OB 7.02 Oc555 OER