Answer:-
The largest decimal values that can represent using 16-bits signed integer is 32,767 (215 − 1). for example when we use the INT_MAX then it is used. which is defined by the INT_MAX.
Explanation:- A 16-bits register can store 216 different values. The signed range of integer values that can be stored in 16 bits is −32,768 (−1 × 215) to 32,767 (215 − 1)
JUSTIFY YOUR ANSWER PLEAS (1 point) What is the largest decimal values you can represent, using...
What is the range of decimal values that can be represented by: a) 6-bit unsigned integer? b) 6-bit signed integer?
1. What is the largest decimal number we can represent with a 16 bit two's complement number? 2. Convert the following signed binary numbers to decimals. 11001 010011 1110100 1100111 3. Convert the following decimal numbers to 6-bit two's complement binary numbers and add them. Note if there is an overflow. 7 + 13 Two's complement/binary number for 7: Two's complement/binary number for 13: Sum: Overflow? 4. Convert the following decimal numbers to 6-bit two's complement binary numbers...
please show your steps and note that question 2 has a byte address of 000002 not 000000. thanks Hex Viewer Case Study to be used for questions 1: Review this excerpt from a hex viewer. You can assume that all data shown is in hex. You can assume that two's complement is used to store signed integers with a 16-bit architecture which is byte addressable. Refer to this excerpt to answer the questions below: 000000 8A00 8E00 CFA1 48BF 7900...
Let x be a signed integer represented using the 12-bit 2's complement scheme. What is the maximum possible value that x can represent? Enter your answer in decimal (base 10)
6 - What decimal number does the bit pattern 0xC0B00000 represent if it is: • [2 pts] A two's complement integer? • [2 pts] An unsigned integer? • [2 pts] A floating point number assuming the IEE 754 single precision format 7 - Perform the following calculations assuming that the values are 8-bit decimal integers stored in two's complement format. Be sure to consider the possibility of overflow. • [2 pts] 10101010 + 00110011 • [2 pts] 10101010 – 00110011...
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