a)
here margin of error E = | 0.030 | |
for96% CI crtiical Z = | 2.05 | |
estimated proportion=p= | 0.520 | |
required sample size n = | p*(1-p)*(z/E)2= | 1166.00 |
(try 1170 if this comes wrong)
b)
here margin of error E = | 0.030 | |
for96% CI crtiical Z = | 2.05 | |
estimated proportion=p= | 0.500 | |
required sample size n = | p*(1-p)*(z/E)2= | 1168.00 |
(try 1172 if this comes wrong)
c)
option C is correct
A television sports commentator wants to estimate the proportion of citizens who "follow professional football Complete...
A television sports commentator wants to estimate the proportion of citizens who "follow professional football." Complete parts (a) through (c). (a) What sample size should be obtained if he wants to be within 4 percentage points with 96% confidence if he uses an estimate of 52% obtained from a poll? The sample size is nothing. (Round up to the nearest integer.) (b) What sample size should be obtained if he wants to be within 4 percentage points with 96% confidence...
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Homework: HW 9.1 9.2 9.3 Score: 0 of 1 pt 17 of 40 (25 complete) 9.1.39 A television sports commentator wants to estimate the proportion of citizens who follow professional football." Complete parts (a) through (c). (a) What sample size should be obtained if he wants to be within 4 percentage points with 95% confidence if he uses an estimate of 48% obtained from a poll? The sample size is 600. (Round up to the nearest integer.) (b) What sample...