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A television sports commentator wants to estimate the proportion of citizens who follow professional football Complete parts
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Answer #1

a)

here margin of error E = 0.030
for96% CI crtiical Z          = 2.05
estimated proportion=p= 0.520
required sample size n =         p*(1-p)*(z/E)2= 1166.00

(try 1170 if this comes wrong)

b)

here margin of error E = 0.030
for96% CI crtiical Z          = 2.05
estimated proportion=p= 0.500
required sample size n =         p*(1-p)*(z/E)2= 1168.00

  (try 1172 if this comes wrong)
c)

option C is correct

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