a) magnetic flux through the flat surface = A*B*cos(theta) (here theta must be the angle between normal to the area and magnetic field)
= A*B*cos(180 - theta)
= -A*B*cos(theta)
= -pi*R^2*B*cos(theta) <<<<<<<<<<<<------------Answer
b) using Gauss' law in magnetism, net magnetic flux through any closed suarfce = 0
magnetic flux through flat surface + magnetic flux through curved surface = 0
magnetic flux through curved surface = -magnetic flux through flat surface
= -(-pi*R^2*B*cos(theta))
= pi*R^2*B*cos(theta) <<<<<<<<<<<<------------Answer
Consider the hemispherical closed surface in the figure below. The hemisphere is in a uniform magnetic...
Flex question A hemispherical close surface of radius R is placed in a uniform field of magni- tude E. i)What would be the flux through the entire closed surface? ii)What is the flux through the dome of the hemisphere? Select one: a. i), ii) ERR b. i), ii) c. i)2ER2, ii) d. i)ETR, ii) e. i)-ErR2, ii)0 f. i)2E+R2, ii)ErR g. 100, ii)-ETR2 Next
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