Question

Styles The circuit shown below uses the following values: E= 12 V R1 = 5.6 KO R2 = 47 KO R3 = 4.7 KO R = 2.2 KO R = 3.3 KO R3 + Un V V unr E R2 RA } V 12 RA mi 4. Calculate : Vi = V2 = V3 = VL = 11 = 12 = 13 = Calculate Vrh Calculate RTH

Answer 1

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Answer 2

SOLUTION :

Req (in KΩ)

= R1 + 1/ [1/R2 + 1/(R3 + RL)] + R4

= 5.6 + 1/[ 1/47 + 1/(4.7 + 3.3)] + 2.2

= 5.6 + 1/(1/47 + 1/8) + 2.2

= 14.6364 

Current  from the battery, I1

= E/Req 

= 12/(14.6364*10^3) 

= 8.2 *10^(-4) amp.

Current through R1 and also R4 = current from battery, I1 :

= 8.2 * 10^(-4) amp.

So, 

V1 = 8.2 * 10(-4) * 5.6 * 10^3 = 4.59 volts

V4 = 8.2 * 10^(-4) * 2.2*10^3 = 1.80 volts

V2 = 12 - V1 - V4 = 12 - 4.59 - 1.80  = 5.61 volts 

I2 = V2/R2 = 5.61/(47*10^3) = 1.19*10^(-4) amp

 Current through R3 and RL , I3 :

= V2/(R3 + RL) 

= 5.61/(8*10^3) = 7.01*10^(-4) amp\.

So,

V3 = 7.01*10^(-4) * 4.7*10^3 = 3.30 volts 

VL = 7.01*10^(-4) * 3.3*10^3 = 2.31 volts

Hence,

V1 = 4.59 volts 

V2 = 5.61 volts

V3 = 3.30 volts

V4 = 1.80 volts 

VL = 2.31 volts 

I1 = 8.2 * 10^-4) amp = 0.82 mA

I2 = 1.19*10^(-4) amp = 0.119 mA = 0.12 mA

I3 = IL = 7.01*10^(-4) amp = 0.701 mA = 0.70 mA 

(ANSWER)