Calculate the solubility of PbCl_2(k_sp=5.09 times10^-15) in a 0.03 M Solution of KCl
I need full explanation, please! A solution of Pb(NO_3)_2 is added to a second solution in which [Cl^-] = [F^-] = [I^-] = [SO_4^2-] = 0.001 M. What is the first precipitate that forms? A) PbI_2 (K_sp = 8.5 times 10^-9) B) PbSO_4 (K_sp= 1.8 times 10^-8) C) PbCl_2 (K_sp = 1.5 times10^-5) D) PbF_2 (K_sp = 3.7 times 10^-8)
Write a solubility product constant expression, K_sp, for an equilibrium in a saturated aqueous solution of the slightly soluble salts Magnesium fluoride, MgF_2 Zinc phosphate, Zn_3(PO_4)_2 Chromium(II) hydroxide, Cr(OH)_3 Strontinum sulfate, SrSO_4. Calculate the solubility in g/L for calcium carbonate, CaCO_3, in pure water given the K_sp = 2.8 times 10^-9. Calculate the solubility in g/L for CaCO_3, in 0.050 M Na_2CO_3.
Calculate the molar solubility of BaSO_4 (K_sp for BaSO_4 = 1.1 times 10 ^-10) a) in water b) in a solution containing 2.00 M SO^2 _4
Calculate the molar solubility of CaF_2 at 25degreeC in a solution of 0.010 M NaF. The solubility-product constant (K_sp) for CaF_2 at 25 degree C is 3.9 x 10^-11
Need help!! The molar solubility of Ba_3(PO_4)_2 is 6.5 times 10^-7 M. Calculate K_sp for Ba_3(PO_4)_2. For Pbl_2 K_sp = 8.7 times 10^-9. Calculate the molar solubility of PbI_2 in 0.100 M Cal_2.
The molar solubility of BaCO_3 (K_sp = 1.6 times 10^-9) in 0.10 M BaCL_2 solution is: 1.6 times 10^-10 4.0 times 10^-5 7.4 times 10^-4 0.10 none of these
The K_sp of AgCl is 1.6 times 10^10. What is the solubility of AgCl in 0.0010 M KCl? Give your answer using scientific notation and to 2 significant figures(i.e., one decimal place).
Calculate the molar solubility of CuX (K_sp = 1.27 times 10^-36) in each of the following. 0.28 M CuCl_2 0.23 M Na_2X
What is the theoretical value of the solubility of KHT in 0.10 M KCl solution? The ksp of KHT in water is 8.34x10^-4
Calculate the solubility of silver chloride in 10.0 M ammonia given the following information: K_sp (AgCI) = 1.6 times 10^-10 Ag^+ (aq) + NH_3(aq) = AgNH_3^+ (aq) K_f1 = 2.2 times 10^3 AgNH_3^+ (aq) NH_3(aq) = Ag(NH_3)_2^+ K_f2 = 8.2 times 10^3