Each of the two pumps (ABC and XYZ) can deliver an actual amount of 100 hp...
6-29. Two pumps are being considered for service in Africa. Each can draw water from a depth of 50 meters and both pumps deliver 60 horsepower (output) to the pumping operation. One of the pumps must be selected. It is expected that the pump will be in use 800 hours per year. The following data are available. If electricity costs $0.14 per kilowatt-hour, which pump should be selected if the MARR is 8% per year? Recall that 1 hp =...
A special-purpose 30-horsepower electric motor has an efficiency of 90%. Its purchase and installation price is $2,200. A second 30-horsepower high-efficiency motor can be purchased for $3,200, and its efficiency is 92%. Either motor will be operated 4,000 hours per year at full load, and electricity costs $0.10 per kilowatt-hour (kWh). MARR = 12% per year, and neither motor will have a market value at the end of the eight-year study period. a. Which motor should be chosen? b. For...
Two 180-horsepower water pumps are being considered for installation in a farm. Financial data for these pumps are in the table below. If power cost is a flat 4 cents per kWh over the study period, determine the minimum number of hours of full-load operation per year that would justify the purchase of the more expensive pump at an interest rate of 10% (1 HP = 746 watts = 0.746 kilowatts). Click the icon to view the additional information. Click...
ABC Brand 1,600 XYZ Brand 5,600 Purchase Price $ Life in Years Salvage Value $ Annual Maintenance $ Efficiency % None 190 None 350 Discrete Compounding; i = 11% Uniform Series Single Payment Capital Recovery Factor To Find A Given P А/Р Compound Amount Present Factor Worth Factor To Find F To Find P Given P Given F P F/ P /F 1.1100 0.9009 1.2321 0.8116 1.3676 0.7312 1.5181 0.6587 1.6851 0.5935 1.8704 0.5346 2.0762 0.4817 2.3045 0.4339 2.5580 0.3909...