Q3 Consider the following Pushdown Automata (the initial stack variable is $). 1, X 0,X 0,$...

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Question

Q3 Consider the following Pushdown Automata (the initial stack variable is $). 1, X 0,X 0,$ X → XX → X$ 1, $ → E 1, X → XX E,

Answer 1

Answer #1

The initial state is p.

First symbol is 0. 0,$ ->X$ . Push X onto stack and be on same state.

Second Symbol 0. 0,X->XX. Push X onto stack and be on same state.

Third symbol 1. 1,X->X. Don't do anything and stay on same state.

Fourth symbol 1. 1,X->X. Don't do anything and stay on same state.

Now after all symbol is over, we always have to indicate end of string.

, X -> which means pop X from stack and go to state p.

This is how the given PDA will work.

If you have any questions comment down and please upvote thanks

Answer 2

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