14. (a) Determine all possible critical point(s) of f(x, y) = x2 + xy + y2...
14. (a) Determine all possible critical point(s) of f(, y) = x2 + xy + y2 - 3.c - 6y. (b) without using the Second Order Partial Derivatives Test (SOPDT), de- termine the nature of the obtained C.P(s). (c) Check your answer in (b) through the (SOPDT). 15. Find a point on the hyperboloid 2z = x2 - y², where the tangent plane is parallel to the plane x - 3y - 2 = 1.
pls solve like example Assign 7.3.25 Find all local extrema for the function f(x,y) = x3 - 12xy + y. Find the local maxima. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. There are local maxima located at (Type an ordered pair. Use a comma to separate answers as needed.) OB. There are no local maxima. Question Hel Find all local extrema for the function f(x,y)=x°-21xy+y3. The function will have local...
Cal 4 , ) and use this to 6. Let f(x,y) = x2 + y2 + 2x + y. (a) Find all critical points of f in the disk {(x,y) : x2 + y2 < 4). Use the second derivative test to determine if these points correspond to a local maximum, local minimum, or saddle point. (b) Use Lagrange multipliers to find the absolute maximum/minimum values of f(x, y) on the circle a2 +y -4, as well as the points...
2 + (a) Determine and sketch the domain of the function f(x, y) = (x2 + y2 – 4) 9 – (x2 + y2). [7] x6 – yo (b) Evaluate lim (x,y)+(1,1) - Y [5] (c) What does it mean to say that a function f(x, y) has a relative minimum at (a,b)? [4] (d) Find all second order partial derivatives of the function f(x,y) = 22y.
(1 point) Consider the function defined by F(x, y) = x2 + y2 except at (r, y) - (0, 0) where F(0,0)0 Then we have (0,0) = (0,0) = ax dy Note that the answers are different. The existence and continuity of all second partials in a region around a point guarantees the equality of the two mixed second derivatives at the point. In the above case, continuity fails at (0,0) Note: You can earn partial credit on this problem...
Minimize f(x,y) = x2 + xy + y2 subject to y = - 6 without using the method of Lagrange multipliers; instead, solve the constraint for x or y and substitute into f(x,y). Use the constraint to rewrite f(x,y) = x² + xy + y2 as a function of one variable, g(x). g(x)=
(b) Find the directional derivative of f(x, y, z) = xy ln x – y2 + z2 + 5 at the point (1, -3,2) in the direction of the vector < 1,0,-1>. (Hint: Use the results of partial derivatives from part(a))
#10 and #12 8. Find all points (.y) where fCx.y) -3x2 + 7xy -4y2 + x + y has possible relative maximum or minimum values 9. Find all points (x,y, z) where f(x,y,z) 5+ 8x 4y+x2+y2 z2has possible relativema imun or minimum value 10. Both first partial derivatives of f(x.y)-x-4xyy are zero at the points (0 11. Find all points (x,y) where f(e.y) 2x2+3xy + 5y has possible relative maximum or minimum values. Then, use the 12. Use the second...
#3 please!! 2. Given the function f(x, y)-x2 +y -2xy -6x - 2y 5, find the following: (a) Find the critical point(s) of the function. For full credit, show all the algebra to find these and give your answer as ordered pairs. (b) Find the second order partial derivatives and use these to find the determinant of each critical point. Then classify each critical point as a saddle point, relative minimum, or relative maximum point. 3. A wine dealer sells...
(1 point) Consider the function defined by ?(?,?)=??(9?2+5?2)?2+?2F(x,y)=xy(9x2+5y2)x2+y2 except at (?,?)=(0,0)(x,y)=(0,0) where ?(0,0)=0F(0,0)=0. Then we have ∂∂?∂?∂?(0,0)=∂∂y∂F∂x(0,0)= ∂∂?∂?∂?(0,0)=∂∂x∂F∂y(0,0)= Note that the answers are different. The existence and continuity of all second partials in a region around a point guarantees the equality of the two mixed second derivatives at the point. In the above case, continuity fails at (0,0)(0,0). (1 point) Consider the function defined by F(x, y) = xy(9x2 + 5y2) x2 + y2 except at (x, y) = (0,0)...