n a group of college students, the ratio of men to women is 3:2 (i.e., 3 to 2). In a recent survey, 65% of the men in this group selected hiking as their favorite outdoor activity whereas 40% of the women in the group selected hiking as their favorite outdoor activity. An individual is randomly selected from this group. What is the probability that hiking is not his/her favorite outdoor activity? Round your result to 2 significant places after the decimal (For example, 0.86732 should be entered as 0.87).
Given,
P(Men) = 3/(3 + 2) = 3/5
P(Women) = 2/(3 + 2) = 2/5
P(Hikin |Men) = 0.65
P(Hiking| Women) = 0.40
So,
P(Hiking is not his/her favorite outdoor activity)
= P(Men)*P(Not hiking | Men) + P(Women)*P(Not hiking | Women)
= (3/5)*(1 - 0.65) + (2/5)*(1 - 0.40)
= 0.45
n a group of college students, the ratio of men to women is 3:2 (i.e., 3...
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2. A committee of 3 is to be selected from a group of 4 men and
4 women. Suppose the selection is made randomly. What is the
probability that the committee consists of at least one women?
use this formula to solve.
We'll often need count the number of ways of sampling k of n items. You may recall this as "n choose k" denoted as n! k!(n - k)! k/
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