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Vectors A and B are shown. What is the magnitude of a vector CfC A+ B? Image description: Vector A of Magnitude 40 and Vector B of Magnitude 50 angled between them is 60 degree angle 40 60° 50 o 10 46 30 0 78
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Answer #1

C = (A2 + B2 + 2 A B cos(theta))1/2

C = (402 + 502 + 2 x 40 x 50 x cos60°)1/2 = 78

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