Question

A uniform magnetic field passes through a horizontal circular wire loop at an angle 16.2° from the normal to the plane of the loop. The magnitude of the magnetic field is 3.15 T, and the radius of the wire loop is 0.270 m. Find the magnetic flux ? through the loop.
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Answer #1

magnetic flux = BA cos

where B = magnetic field

A = area

= angle between magnetic field and area vector

= 3.15*pi*0.27^2* cos 16.2

= 0.7 Wb

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