Question

The reactant concentration in a zero-order reaction was 0.100 M after 165 s and 2.50×10⁻²M after 345 s, and the rate constant of the reaction is 4.17*10

The integrated rate laws for zero-, first-, and second-order may be arranged such that they resemble the equation for a straight mac b. ne,y Order Integrated Rate Law Graph Slope vs. t k

What was the initial reactant concentration for the reaction described in Part A?

Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash.

Answer 1

foe zero order :

[A] = - kt + [A]o

[A]o = iniitial concentration

[A] = remaining concentration

k = rate constant = 0.1 - 2.5 x 10^-2 / 345 - 165

    = 4.17 x 10^-4

t = time

[A] = - kt + [A]o

0.100 = - 4.17 x 10^-4 x 165 + [A]o

[A]o = 0.169 M

initial reactant concentration = 0.169 M