Question

An alpha particle is a helium nucleus and therefore consists of two protons and two neutrons. Such particle has an initial velocity of +1.60*10^3 m/ s x and enters a region where the electric field is E =- 500.N / C x .

a) How much time passes before the alpha particle comes to rest? b) How far has the alpha particle traveled during this time?

b) How far has the alpha particle traveled during this time?

Answer 1

Answer 2

Here

Work Done = Loss in Kinetic Energy

Threfore

Eq*s = 0.5*m*v^2

500*(2*1.6*10^-19)*s = 0.5*6.64*10^-27*(1.60*10^3)^2

s = 0.00005312 m

= 5.3*10^-5 m

As we know that

v = u + at

a = Eq/m

= (500*2*1.6*10^-19)/(6.64*10^-27)

Therefore

t = (1.60*10^3)/( (500*2*1.6*10^-19)/(6.64*10^-27))

= 6.64*10^-8 sec

Answer 3

:P