Question

Duplicate problem using the command created in MATLAB and find the equivalent resistance for the circuit

Find the power dissipated in the 3 k Ω resistor in the circuit in Fig. P3.49. Figure P3.49 750 2 25 kΩ 192 V Bridge structure is balanced therefore 15-5 = 3·25, the current flows by 5ΚΩ behaving as an open circuit Determining equivalent resistance in 192V source: R192,-750 + (15000 + 3000*25000 + 5000-750 + (18000 30000) 18000 30000 750 + ( -750 + 11250 = 12kΩ 1800030000 192 12000= 16mA 4 = i ( ) = (16m) (30k + 18x) = (16mA) (301 ) = (16mA)(0.625)-10mA 30k 18k 48k Power dissipated in 3ΚΩ p -(i1)(R) (10mA)2 (3000) (10 10-3)2(3000) 10-4(3000) 3000mW

Answer 1