The structure of the compound A and B is with the molecular formula C9H10O2 AND C18H18O2 respectively is given in the image below:
In the IR spectrum, the two most intense bands will be obtained for C=O and C-O groups. In addition to these, C=C aromatic stretching frequency band will be obtained and C-H stretching for methyl and the aromatic group can also be noticed.
please help! c 3.86 ppm, singlet, 3H d-2.52 ppm, singlet, 3H Compound A: CoH1002 TSI a...
V. Draw the structures of Compound 23A (6 pts). Compound 23B (6 pts) and clearly indicate your assignments of all proton resonances using the lower case letter associated with the signal (6 pts). Calculate the Unsaturation Index of each compound (2 pts) (20 points total) 1.24 126 25 e = 1.25 ppm 20 doublet, 6H a = 10.0 ppm 1.5 singlet, 1H 10 00 10 0.5 Compound 23a: CH,20 Unsat. Index = (2C+2-H-X+N¥2 = 70 7.09 X=number of halogens b=7.84...
organic V. Draw the structures of Compound 23A (6 pts). Compound 23B (6 pts) and clearly indicate your assignments of all proton resonances using the lower case letter associated with the signal (6 pts). Calculate the Unsaturation Index of each compound (2 pts) (20 points total) 30 e = 1.25 ppm doublet, 6H 25 20 a = 10.0 ppm, 15 singlet, 1H 709 7.07 Unsat. Index = (2C+2-H-X+N)/2 = X=number of halogens d=3.0 ppm, septet, 1H 1000 Compound 23a: CH,...
V. Draw the structures of Compound 23A (6 pts), Compound 23B (6 pts) and clearly indicate your assignments of all proton resonances using the lower case letter associated with the signal (6 pts). Calculate the Unsaturation Index of each compound (2 pts) (20 points total) 1.24 3.0 1.26 2.5 e = 1.25 ppm doublet, 6H 2.0 a = 10.0 ppm 1.5 Compound 23a: C10H420 singlet, 1H 10.00 7.83 7.85 7.09 7.07 1.0 Unsat. Index = (2C+2-H-X+N)/2 = X=number of halogens...
V. Draw the structures of Compound 23A (6 pts), Compound 23B (6 pts) and clearly indicate your assignments of all proton resonances using the lower case letter associated with the signal (6 pts). Calculate the Unsaturation Index of each compound (2 pts) (20 points total) 1.24 3.0 1.26 2.5 e = 1.25 ppm doublet, 6H 2.0 a = 10.0 ppm 1.5 Compound 23a: C10H420 singlet, 1H 10.00 7.83 7.85 7.09 7.07 1.0 Unsat. Index = (2C+2-H-X+N)/2 = X=number of halogens...
18. Draw the structures of Compound 18a. and 18b. (18 pts), clearly indicate your assignments of all proton resonances (8 pts). Calculate the Unsaturation Index of each compound (4 pts) (30 points total) 3.0 2.00 Unsat. Index = (2C + 2 - H - X + N)/2 = 2.5 e = 2.00 ppm, singlet, 2H f = 1.27 ppm, 4.90 2.0 7.20 Compound 18a: C1,4402 triplet, 3H d = 2.66 ppm, 1.27 1.5 c = 4.90 ppm, quartet, 2H a...
18. Draw the structures of Compound 18a. and 18b. (18 pts), clearly indicate your assignments of all proton resonances (8 pts). Calculate the Unsaturation Index of each compound (4 points) (30 points total) 2.0 3.64 Unsat. Index = (2C + 2-H-X +N)/2 = 1.5 1.06 6.86 7.00 d = 2.44 ppm, Compound 18a. C,H, N 1.0 7.02 6.84 quartet, 2H 2.43 2.45 1.08 1.04 a = 7.01 ppm, b = 6.85 ppm, c = 3.64 ppm, 0.5 doublet, 2H doublet,...
20 3.64 Unsat. Index = (2C+2-H-X +N)/2 = 15 6.85 7.00 d=2.44 ppm, Compound 18a. CHN quartet, 2H 1.0 7.02 6.84 108 c=3.64 ppm, 245 a = 7.01 ppm, doublet, 2H b = 6.85 ppm, doublet, 2H 05 singlet, 2H 241 e=1.06 ppm, triplet, 3H 0,0 8.0 75 70 6.5 60 55 8, ppm 30 1) MeMgBr 12) H20, H30* 5.0 45 40 35 25 20 1.5 1.0 0.5 3D 100 205 5500-5000) e = 2.05 ppm, singlet, 3H f...
18. Draw the structures of Compound 18a. and 18b. (18 pts), clearly indicate your assignments of all proton resonances (8 pts). Calculate the Unsaturation Index of each compound (4 points) (30 points total) 2.0 3.64 Unsat. Index = (2C+2-H-X +N)/2 = 1.5 1.06 6.86 7.00 d = 2.44 ppm, Compound 18a. C10H,,N quartet, 2H 1.0 7.02 6.84 2.43 2.45 c = 3.64 ppm, 1.08 1.04 a = 7.01 ppm, b = 6.85 ppm, doublet, 2H doublet, 2H singlet, 2H 0.5...
18. Draw the structures of Compound 18a. and 18b. (18 pts), clearly indicate your assignments of all proton resonances (8 pts). Calculate the Unsaturation Index of each compound (4 points) (30 points total) 20 3.64 Unsat. Index = (2C+2-H-X+N)/2 = 15 6.96 7.00 d = 2.44 ppm, 10 Compound 18a. CHN 70 6.84 quartet, 2H a = 7.01 ppm, b = 6.85 ppm, c = 3.64 ppm, 243 108 104 05 doublet, 2H doublet, 2H singlet, 2H 241 247 e...
organic V. Draw the structures of Compound 23A (6 pts), Compound 23B (6 pts) and clearly indicate your assignments of all proton resonances using the lower case letter associated with the signal (6 pts). Calculate the Unsaturation Index of each Compound (2 pts) (20 points total) 1.24 30 1 25 e = 1.25 ppm 2.5 doublet, 6H 20 a = 10.0 ppm Compound 23a: C10H2O 15 singlet, 1H 7.83 7.85 7.09 707 Unsat. Index = (2C+2-H-X+N/2= X=number of halogens d=3.0...