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Stephen is given a large crystal and needs to it is a diamond or cubic zirconia. He shines a beam of light at a 40.1 angle up

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Answer #1

nd = index of refraction for diamond = 2.419

nz = index of refraction for zirconia = 2.176

na = index of refraction of air = 1

= angle of incidence = 40.1 deg

rd = angle of refraction in case of diamond

rz = angle of refraction in case of zirconia

Using snells law for diamond

na Sin = nd Sinrd

(1) Sin40.1 = (2.419) Sinrd

rd = 15.4 deg

Using snells law for cubic zirconia

na Sin = nz Sinrz

(1) Sin40.1 = (2.176) Sinrz

rz = 17.2 deg

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