Question

Write a recursive function in Python to find the sum of digits of a number. Name the function sum_of_digits. The function should use recursive algorithm (calling itself). The function should print out the sum of all the digits of a given number. For example, sum_of_digits(343) should have a output of 10. Marks will be deducted if you do not follow strictly to the instructions.

[3]: N 1 def sum_of_digits(n): HNM in sum_of_digits (343) Out[3]: 10

Answer 1

PROGRAM:

# Definition of sum_of_digits() function
def sum_of_digits(n):
    if(n==0):
        return n
    else:
        # rem = n%10
        # div = n/10
        # return rem + sum_of_digits(div)
        return n%10 + sum_of_digits(n/10)

# Taking input number from user
number = int(input('Enter a number: '))
# Calling sum_of_digits() function and storing the return value in result
result = int(sum_of_digits(number))
# Printing the result
print("Sum of digits of " + str(number) + " is " + str(result))

Please refer to the following screenshot of the program for indentation of the code:

SAMPLE OUTPUTS:

# Definition of sum_of_digits() function def sum_of_digits (n): if(n==0): return n else: rem = n$10 div = n/10 return rem + sum_of_digits (div) PUREBOJU # Taking input number from user number = input ( 'Enter a number: ') # Calling sum_of_digits() function and storing the return value in result result = sum_of_digits (number) # Printing the result print("Sum of digits of " + str(number) + " is " + str (result))

Enter a number: 343 Sum of digits of 343 is 10 Process finished with exit code 0

Enter a number: 12396 Sum of digits of 12396 is 21 Process finished with exit code 0