Using the table below, conduct a test to determine whether the proportion of children with frequent ear infections in non-smoking households is different than 50%. What is the appropriate p-value?
Non-smoking household |
Smoking household |
|
Infrequent ear infections |
69 |
22 |
Frequent ear infections |
45 |
29 |
p = 0.04 |
||
p = 0.02 |
||
p = 0.01 |
||
p = 0.33 |
Let "p" be the proportion of children with frequent ear infections in non-smoking households.
In a random sample of n=114 individuals 45 have Frequent ear infections.
Therefore,
We wan to test the claim that the proportion of children with frequent ear infections in non-smoking households is different than 50%.
The hypothesis testing problem is:
the test statistic is:
The p-value is
### By using z table: P(z<=-2.24)=0.0125
More accurately by using Excel: p=0.024
=2*NORMDIST(-2.242,0,1,1)
Therefore the correct choice is p=0.02
Using the table below, conduct a test to determine whether the proportion of children with frequent...
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