Question

Using the table below, conduct a test to determine whether the proportion of children with frequent...

Using the table below, conduct a test to determine whether the proportion of children with frequent ear infections in non-smoking households is different than 50%. What is the appropriate p-value?

Non-smoking household

Smoking household

Infrequent ear infections

69

22

Frequent ear infections

45

29

p = 0.04

p = 0.02

p = 0.01

p = 0.33

0 0
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Answer #1

Let "p" be the proportion of children with frequent ear infections in non-smoking households.

In a random sample of n=114 individuals 45 have Frequent ear infections.

Therefore,

We wan to test the claim that the proportion of children with frequent ear infections in non-smoking households is different than 50%.

The hypothesis testing problem is:

the test statistic is:

The p-value is

### By using z table: P(z<=-2.24)=0.0125

More accurately by using Excel: p=0.024

=2*NORMDIST(-2.242,0,1,1)

Therefore the correct choice is p=0.02

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