A spherical drop of mercury of radius R has a capacitance given by Cm = 4piepsilonoR. If 8 such drops combine to form a single larger drop, what is its capacitance? Give your answer in terms of Cm
Given : n = 8 ; Cm = 40R
Solution :
As given ,8 drops combine to form a single large drop.
Volume of big drop = 8 times the volume of a small drop
Volume of sphere = (4/3)R3
Since volume is proportional to the radius cubed . Hence the radius of combined drop is given by : R = 81/3 = 2 times that of smaller drop.
As capacitance is directly proportional to the radius. The capacitance will also be increased by the same factor.
i.e. C = 2Cm
Answer : C = 2 Cm
A spherical drop of mercury of radius R has a capacitance given by Cm = 4piepsilonoR....
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