You are doing a chi- square test for independence and find a significant result. What can...
You are doing a chi- square test for independence and find a significant result. What can conclude? A The null hypothesis is correct and there is no difference in the proportion of count in your single row. B . The null hypothesis is incorrect and there is probably a relationship between the two variables of interest. C.The null hypothesis is correct and there is no relationship between your two variables of interest. D.The null hypothesis is incorrect and there is probably a difference in the proportion of counts un your single row.
Homework Answers
If we are doing a chi-square test for independence and find a significant result;
The null hypothesis is incorrect and there is probably a relationship between the two variables of interest (As there is significance)
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You are doing a chi- square test for independence and
find a significant result. What can...
You are doing a chi- square test for independence and find a significant result. What can conclude? A The null hypothesis is correct and there is no difference in the proportion of count in your singl...
You are doing a chi- square test for independence and find a significant result. What can conclude? A The null hypothesis is correct and there is no difference in the proportion of count in your single row. B . The null hypothesis is incorrect and there is probably a relationship between the two variables of interest. C.The null hypothesis is correct and there is no relationship between your two variables of interest. D.The null hypothesis is incorrect and there is...
Chi-Square Test for Independence Using Chi-Square, we are looking to see if there is a significant...
Chi-Square Test for Independence Using Chi-Square, we are looking to see if there is a significant difference between what we would expect results to be, and what the actual results were. That is, expected vs. observed. Use alpha = .05 Listed below are data from a survey conducted recently where Males and Females responded to their happiness with their supervisor (this is fictitious data). Response Male Female Total Not at all 23 25 48 Somewhat 13 22 35 Very 26 16 42...
Question 1 In a chi -square test of independence , the null hypothesis states that-----------. a....
Question 1 In a chi -square test of independence , the null hypothesis states that-----------. a. the two variables of interest are related in the population. b. the column frequencies equal the row frequencies c. the sum of the and the column frequencies equal the total frequency d. the two variables of interest are unrelated in the population Question 2 A survey asked people whether they identified as a morning person, night person, or had no preference. a. 270 replied...
The chi-square test for independence is similar to a correlation in that it evaluates the relationship...
The chi-square test for independence is similar to a correlation in that it evaluates the relationship between two variables. True or false. Explain your answer.
6 - The null hypothesis for a chi-square contingency test of independence for two variables...
The null hypothesis for a chi-square contingency test of independence for two variables always assumes that the variables are independent.AnswerTrueFalse
In order to receive credit for the homework, you must show all steps for doing a chi square test of independence. T...
In order to receive credit for the homework, you must show all steps for doing a chi square test of independence. These steps include: null and alternative hypothesis); critical value; calculations (show work); reject or accept H; results statement using no relationship or a relationship. A random sample of 500 voters were selected and asked their opinion on tax reform. The sample was further divided into Democrats and Republicans. The following table gives the results of the poll. At a...
In order to receive credit for the homework, you must show all steps for doing a chi square test of independence....
In order to receive credit for the homework, you must show all steps for doing a chi square test of independence. These steps include: null and alternative hypothesis); critical value; calculations (show work); reject or accept H; results statement using no relationship or a relationship. The operations manager of a company that manufactures tires wants to determine whether there are any differences in the quality of workmanship among the 2 daily shifts. The manager randomly selects 385 tires and carefully...
Does the data meet the conditions for the chi-square test? StatCrunch Instructions: Test of Independence Using...
Does the data meet the conditions for the chi-square test?
StatCrunch Instructions: Test of Independence Using
Technology
Next we will use StatCrunch to calculate the expected
counts:
Enter Yes and No in column var1.
Enter the observed counts as they appear in the table above
(not including the totals) into columns var2 and var3.
Rename: var1 as "911", var2 as "No Risk" and var3 as "M to S
Risk"
Choose Stat -> Tables -> Contingency -> with
summary
Select the...
11. Effect size for the chi-square test for independence Aa Aa Which of the following statements...
11. Effect size for the chi-square test for independence Aa Aa Which of the following statements are correct about the phi-coefficient? Check all that apply. It is determined only by the proportions in a 2 x 2 data matrix. It is the same as Cramer's V when the data are a 2 x 2 matrix. It can be used as a measure of the significance of a relationship between two dichotomous variables. * It can be used as a measure...
What conditions must be met to apply a chi-square test for independence on the Friendship Gender...
What conditions must be met to apply a chi-square test for independence on the Friendship Gender data set? O Observed counts are from appropriately selected random samples and the difference between observed and expected counts is approximately normally distributed. Observed counts are from appropriately selected random samples and the sample size is at least 30 for application of the central limit theorem. Observed counts are from i appropriately selected random samples and the population distribution is normally distributed Observed counts...
In order to receive credit for the homework, you must show all steps for doing a chi square test of independence. These steps include: null and alternative hypothesis); critical value; calculations (show work); reject or accept H; results statement using no relationship or a relationship. A random sample of 500 voters were selected and asked their opinion on tax reform. The sample was further divided into Democrats and Republicans. The following table gives the results of the poll. At a...
In order to receive credit for the homework, you must show all steps for doing a chi square test of independence. These steps include: null and alternative hypothesis); critical value; calculations (show work); reject or accept H; results statement using no relationship or a relationship. The operations manager of a company that manufactures tires wants to determine whether there are any differences in the quality of workmanship among the 2 daily shifts. The manager randomly selects 385 tires and carefully...
Does the data meet the conditions for the chi-square test?
StatCrunch Instructions: Test of Independence Using
Technology
Next we will use StatCrunch to calculate the expected
counts:
Enter Yes and No in column var1.
Enter the observed counts as they appear in the table above
(not including the totals) into columns var2 and var3.
Rename: var1 as "911", var2 as "No Risk" and var3 as "M to S
Risk"
Choose Stat -> Tables -> Contingency -> with
summary
Select the...
11. Effect size for the chi-square test for independence Aa Aa Which of the following statements are correct about the phi-coefficient? Check all that apply. It is determined only by the proportions in a 2 x 2 data matrix. It is the same as Cramer's V when the data are a 2 x 2 matrix. It can be used as a measure of the significance of a relationship between two dichotomous variables. * It can be used as a measure...
What conditions must be met to apply a chi-square test for independence on the Friendship Gender data set? O Observed counts are from appropriately selected random samples and the difference between observed and expected counts is approximately normally distributed. Observed counts are from appropriately selected random samples and the sample size is at least 30 for application of the central limit theorem. Observed counts are from i appropriately selected random samples and the population distribution is normally distributed Observed counts...
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