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In each of the situations, choose whether or not the given assignment of probabilities to individual...

In each of the situations, choose whether or not the given assignment of probabilities to individual outcomes is legitimate. Remember, a legitimate model need not be a practically reasonable model. If the assignment is not legitimate, choose the correct reason for your answer.

(a) Roll a six‑sided die and record the count of spots on the up‑face:

?(1)=0,?(2)=1/6,?(3)=1/3,?(4)=1/3,?(5)=1/6,?(6)=0P(1)=0,P(2)=1/6,P(3)=1/3,P(4)=1/3,P(5)=1/6,P(6)=0 .

This is not a legitimate model because the sum of the probabilities does not equal 11 .

This is not a legitimate model because you cannot have a probabiltiy of 00 .

This is a legitimate model.

This is not a legitimate model because one of the probabilities is greater than 11 .

(b) Deal a card from a shuffled deck:

?(clubs)=12/52P(clubs)=12/52 ,  ?(diamonds)=12/52P(diamonds)=12/52 , ?(hearts)=12/52P(hearts)=12/52 , ?(spades)=16/52P(spades)=16/52 .

This is a legitimate model.

This is not a legitimate model because you also need to consider the probability of the face cards.

This is not a legitimate model because the sum of the probabilities does not equal 11 .

This is not a legitimate model because one of the probabilities is greater than 11 .

(c) Choose a college student at random and record sex and enrollment status:

?(female full‑time)=0.56,?(female part‑time)=0.24,?(male full‑time)=0.44,?(male part‑time)=0.17P(female full‑time)=0.56,P(female part‑time)=0.24,P(male full‑time)=0.44,P(male part‑time)=0.17 .

This is not a legitimate model because the sum of the probabilities is greater than 11 .

This is not a legitimate model because you cannot combine the probability of sex and enrollment status.

This is a legitimate model.

This is not a legitimate model because one of the probabilities is greater than 11 .

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