Hydrogen peroxide is made by white blood cells to destroy harmful bacteria. When hydrogen peroxide decomposes, it forms molecular oxygen and water. 2 H2O2(aq) ⟶ O2(g) + 2 H2O(g) Suppose O2 is being formed at a rate of 0.65 M/min. At what rate (M/min) is the concentration of hydrogen peroxide changing? Enter your answer to 2 decimal places.
This minus sign only indicates that the concentration of the reactant (H2O2) is decreasing.
Hydrogen peroxide is made by white blood cells to destroy harmful bacteria. When hydrogen peroxide decomposes,...
26. Hydrogen peroxide decomposes into water and oxygen in a first-order process. H2O2(aq) → H2O(l) + 1/2 O2(g) 26. Hydrogen peroxide decomposes into water and oxygen in a first-order process. H2O2(aq) → H2O(2) + 1/2O2(g) At 20.0 °C, the half-life for the reaction is 3.05 x 104 seconds. If the initial concentration of hydrogen peroxide is 0.52 M, what is the concentration after 8.00 days?
1) Hydrogen peroxide, H2O2(aq), decomposes to H2O(l) and O2(g) in a reaction that is first order in H2O2 and has a rate constant k = 1.06×10−3 min−1 at a given temperature. How long will it take for 15% of a sample of H2O2 to decompose? 2)The decomposition of nitrogen dioxide, NO2, into nitrogen monoxide and oxygen at a high temperature is second-order in NO2. The rate constant for this reaction is 3.40 L/mol×min. Determine the time needed for the concentration...
Please show work I am not getting the correct answers 1. Hydrogen peroxide, H2O2, decomposes spontaneously through the following reaction. 2H2O2(aq) 2H2O(g) + O2(g) The kinetics are second order, and the half‐life is 17.3 min when a 1.75 M solution of H2O2 is made. What is the concentration of the solution after 24.8 min? 2. The decomposition of N2O5 occurs by the following reaction: 2N2O5(g) 4NO2(g) + O2(g) The rate constant is experimentally determined to be 3.4 x 10‐4 s‐1....
One way that white blood cells kill bacteria is by using hydrogen peroxide. Based on this information would you expect pathogenic bacteria to be catalase positive or negative? Explain.
Hydrogen peroxide (H2O2) decomposes to produce water and oxygen according to the following reaction: 2 H2O2 (l) -----------> 2 H2O (l) + O2 (g) Which relationship regarding the quantities of reactants and products associated with this reaction is NOT correct? Group of answer choices 2 molecules of H2O2 -----------------> 2 molecules of H2O + 1 molecule of O2 2 mol of H2O2 ----------------->2 mol of H2O + 1 mol of O2 68.0 g of H2O2 -----------------> 36.0 g of H2O...
K= 1.54day-1 Hydrogen peroxide is used to disinfect porous surfaces like N95 masks by heating the liquid to 100C to make a vapor. Hydrogen peroxide liquid is stored as a 3.0% w/w solution at room temperature, but it quickly decomposes into water and oxygen in a first-order process. H2O2(aq) + H2O(l) + 1/2 O2(g) 4) If the initial concentration of Hydrogen peroxide is 0.52 M, what is the H2O2 concentration after 7.00 days? Use the equation In (X/Xf=kt a) 0.000012...
Part A Hydrogen peroxide decomposes to water and oxygen at constant pressure by the following reaction. 2 H2O2() + 2 H2O(1) + O2() AH =-196 kJ Calculate the value of (kJ) in this exothermic reaction when 3.00 g of hydrogen peroxide decomposes at constant pressure? -1.73 x 104 kJ -0.0289 kJ -8.65 kJ -17.3 kJ 1.92 kJ Submit Reguest Answer
The decomposition of hydrogen peroxide in dilute sodium hydroxide at 20 °C H2O2(aq)H2O(l) + ½ O2(g) is first order in H2O2 with a rate constant of 1.10×10-3 min-1. If the initial concentration of H2O2 is 5.66×10-2 M, the concentration of H2O2 will be 9.34×10-3 M after _______ min have passed.
The decomposition of hydrogen peroxide in dilute sodium hydroxide at 20 °C H2O2(aq) ------> H2O(l) + ½ O2(g) is first order in H2O2 with a rate constant of 1.10×10-3min-1. If the initial concentration of H2O2 is 5.52×10-2 M, the concentration of H2O2 will be 1.56×10-2 M after _____ min have passed.
Over time, hydrogen peroxide, H2O2, degrades into water and oxygen gas. A bottle of hydrogen peroxide is expired and you need to determine the concentration. A titration is performed using the following equation: 3 H2O2(aq) + 2 NaMnO4(aq) → 3 O2(g) + 2 MnO2(aq) + 2 NaOH(aq) + 2 H2O(l) Note that permanganate ion, MnO4-, is purple, while manganese (IV) ion, Mn4+, is colorless. A quantity of 683 mL of 3.44 M NaMnO4 was measured and placed in a beaker. The solution...