Find the mean of the given probability distribution.
The probabilities that a batch of 4 computers will contain 0, 1,2,3, and 4 defective computers are 0.4979, 0.3793, 0.1084, 0.0138, and 0.0007, respectively. Round answer to the nearest hundredth.
x | 0 | 1 | 2 | 3 | 4 |
P(X) | 0.4979 | 0.3793 | 0.1084 | 0.0138 | 0.0007 |
Mean = X * P(X)
= 0 * 0.4979 + 1 * 0.3793 + 2 * 0.1084 + 3 * 0.0138 + 4 * 0.0007
= 0.6403
Find the mean of the given probability distribution. The probabilities that a batch of 4 computers...
The probabilities that a batch of computers will contain XX defective computers are are given below. Find the standard deviation for the probability distribution. Round answer to the nearest hundredth. XP(X) -------------------------------------------------------------- 0|0.5333330 1|0.2333331 2|0.2333332 3|0.0000003 What is the standard deviation for this probability distribution? SELECT ALL APPLICABLE CHOICES A)σ=0.82260 B)σ=1.1235 C)σ=1.2243 D)σ=0.92135 E)σ=1.2134 F) None of These
Determine whether a probability distribution is given. If a probability distribution is given, find its mean. (Round to the nearest thousandth). If a probability distribution is not given, state (not a probability distribution). (Check your spelling!) x P(x) 0 0.658 1 0.287 2 0.050 3 0.004 4 0.001
Find the missing value required to create a probability distribution, then find the standard deviation for the given probability distribution. Round to the nearest hundredth. x / P(x) //////// 0 / 0.09 1 / 2 / 0.17 3 / 0.18 4 / 0
4.3.6 Assume the Poisson distribution applies. Use the given mean to find the indicated probability Find P(4) when μ 5. P(4)- Round to the nearest thousandth as needed.) Enter your answer in the answer box and then click Check Answer All parts showing Clear All
Suppose we are given a probability distribution that has a mean if 12 and a standard deviation of 0.2. Use the Chebyshev inequality to find a lower bound estimate of the following probabilities: (a) The probability that the outcome will lie between 10 and 14 (b) The probability that the outcome lies between 10.5 to 13.5 Problem #1(a): Round your answer to 4 decimals. Problem #1(b): Round your answer to 4 decimals.
Find the standard deviation for the given probability distribution. Round to the nearest hundredth. X P(x) 0 0.09 10.34 20.23 30.12 4. 0.22 O A. o = 1.70 OB. o = 1.30 O C. o = 1.34
Use the probability distribution to find probabilities in parts (a) through (c). The probability distribution of number of dogs per household in a small town Dogs 0 1 2 3 4 5 Households 0.6730.673 0.2010.201 0.0760.076 0.0250.025 0.0170.017 0.0080.008 (a) Find the probability of randomly selecting a household that has fewer than two dogs. 0.8740.874 (Round to three decimal places as needed.) (b) Find the probability of randomly selecting a household that has at least one dog. nothing (Round...
Use the probability distribution to find probabilities in parts (a) through (c). The probability distribution of number of dogs per household in a small town Dogs 0 1 2 3 4 5 Households Use the probability distribution to find probabilities in parts (a) through (c). The probability distribution of number of dogs per household in a small town Dogs 0 1 2 3 4 5 Households 0.6780.678 0.1940.194 0.0790.079 0.0270.027 0.0170.017 0.005
A police department reports that the probabilities that a X burglaries will be reported in a given day are given below. Find the standard deviation for the probability distribution. Round answer to the nearest hundredth A) B) 1.3 ơ 0.67 C) D) None of These P(X) 0 | 9.805e -6 1 0.0004430 20.008011 0.07239 40.3271 5| 0.5918 What is the standard deviation for this probability distribution?
Use the probability distribution to find probabilities in parts (a) through (c).The probability distribution of number of dogs per household in a small townDogs 0 1 2 3 4 5Households 0.680 0.191 0.079 0.029 0.0130 0. 008(a) Find the probability of randomly selecting a household that has fewer than two dogs.0.871 (Round to three decimal places as needed.)(b) Find the probability of randomly selecting a household that has at least one dog.0.320 (Round to three decimal places as needed.) (c)...