A rocket accelerates upward at a rate of 28.5 m/s until it reaches a height of 100 meters above the ground where the engine shuts down. What is the maximum height the rocket will obtain?
We know the equation of motion
Where, v is final velocity of the object
u is initial velocity of the object
a is acceleration of the object
S is total displacement of the object
For the given problem (after the 100 m journey),
u = 28.5 m/s (when engine stops the velocity of rocket was 28.5 m/s)
v = 0 m/s (at maximum height)
a = -g = -9.8 m/s2 (acceleration due to gravity)
Putting all the values in the equation of motion, we get
or,
or,
Hence, the maximum height reached by the rocket is 100 + 41.44 = 141.44 m .
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