Question

3. Use a 0.05 level of signigicance to test Bill Bradley's claim that the majority of voters would vote for him. Assume that sample data consist of 1068 randomly selected voters, 540 of whom indicated that they would vote for Bradley.

4. The Sylvan Pharmaceutical Company makes tubes of anti bacterial cream that are labeled as containing 4 oz. In testing the claim that the mean content amount is less than 4 oz, a P-value of 0.220 is obtained, What do you conclude?

Answer 1

3)

Below are the null and alternative Hypothesis,
Null Hypothesis: p = 0.5
Alternative Hypothesis: p > 0.5

Rejection Region
This is right tailed test, for α = 0.05
Critical value of z is 1.64.
Hence reject H0 if z > 1.64

Test statistic,
z = (pcap - p)/sqrt(p*(1-p)/n)
z = (0.5056 - 0.5)/sqrt(0.5*(1-0.5)/1068)
z = 0.37

P-value Approach
P-value = 0.3557
As P-value >= 0.05, fail to reject null hypothesis.

4)
This is a one tailed test

p value = 0.220

We fail to reject the null hypothesis at 0.05 significance level