Question

The manufacturer of a laser printer reports the mean number of pages a cartridge will print before it needs replacing is 12, 275. The distribution of pages printed per cartridge closely follows the normal probability distribution and the standard deviation is 745 pages. The manufacturer wants to provide guidelines to potential customers as to how long they can expect a cartridge to last.

How many pages should the manufacturer advertise for each cartridge if it wants to be correct 99 percent of the time? (Round your z value to 2 decimal places and the final answer to the nearest whole number.)

Answer 1

as 99 percent correct, the value should be at 1st percentile:

for 1st percentile critical value of z=		-2.33
therefore corresponding value=mean+z*std deviation=			10539.15 ~ 10539