The amount of time students study for a final exam is normally distributed with a mean of 25 hours and a standard deviation of 4.0 hours. What is the probability that a student will study for more than 26 hours?
a).2500
b).4013
c).5987
d) .6554
Solution :
Given that,
mean = = 25
standard deviation = = 4
P(x >26 ) = 1 - P(x< 26)
= 1 - P[(x -) / < (26-25) /4 ]
= 1 - P(z <0.25 )
Using z table
= 1 - 0.5987
probability= 0.4013
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