Solution:
Total 52 cards
Spade cards 13
In this 13 , a card of "Three of spade"
Consider 2 cards are selected without replacement.
P(1st card is of "Three of spade") = 1/52
Now , 51 cards are remaining. Out of 51 , there are 12 cards of spade
P(Second card is a spade) = 12/51
So ,
Required probability
= P(1st card is of "Three of spade" AND 2nd card is a spade)
= [1/52]*[12/51]
= 12/[52*51]
= 1/221
= 0.00452488687
Answer : Required probability = 1/221 = 0.00452488687
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