Consider a knapsack cryptosystem with public key (18, 30, 7, 26) and n = 47. Encrypt...

Question

Question

Consider a knapsack cryptosystem with public key (18, 30, 7, 26) and n = 47. Encrypt last four bits of the "C."

Answer 1

Answer #1

--> public key = (18, 30, 7, 26)

--> n = 6

--> message = "C"

--> message in binary = "01000011"

--> Last four bits = "0011"

--> So, the encryption is done as follows:

= 0*18 + 0*30 + 1*7 + 1*26

= 33

--> Cipher text is 33

Answer 2

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