In a random sample of 500 U.S. citizens, 268 said that they plan to vote in the upcoming election. a. Construct a 90% confidence interval for the proportion of all U.S. citizens who would say they plan to vote in the upcoming election. b. Explain why the interval does or does not indicate that a majority of U.S. citizens would say they plan to vote in the upcoming election. c. Explain why the interval does or does not indicate the proportion of all U.S. citizens
In a random sample of 500 U.S. citizens, 268 said that they plan to vote in...
Question 2: A survey of 800 randomly selected senior citizens showed that 55% said they planned to watch the upcoming town hall debate on television. The margin of error for the 95% confidence interval is 3.5 percentage points. Part 1 (calculation) Write down the 95% confidence interval for the proportion of all senior citizens who plan to watch the upcoming debate on television. Be sure to show your work. Part 2 (interpretation) Does the confidence interval support the claim that...
A random sample of 78 students were interviewed and 59 said they would vote for a democrat in the 2008 election. 1. Let p represent the proportion of all students at this college who will vote for a democrat. Find a point estimate p for p. 2. Find a 90% confidence interval for p. 3. What assumptions are required for the calculations of part (b)? Do you think these assumptions are satisfied? Explain 4. How many more students should be...
Random sample of 330 voters, finding 144 who says that will vote “yes” on the upcoming school budget e chronicle polls a random sample of 330 voters, finding 144 who says that will vote "yes" on the upcoming school budget. What is the value of the sample proportion? What is the value of the standard error? Have we met the conditions to construct a 1-proportion z interval? Construct a 95% confidence interval for the actual sentiment of all the voters.
In a randomly selected sample of 500 registered voters in a community, 260 individuals say that they plan to vote for Candidate Y in the upcoming election. (a) Find the sample proportion planning to vote for Candidate Y. (Round your answer to two decimal places.) (b) Calculate the standard error of the sample proportion. (Round your answer to three decimal places.) (c) Find a 95% confidence interval for the proportion of the registered voter population who plan to vote for...
In a randomly selected sample of 500 registered voters in a community, 320 individuals say that they plan to vote for Candidate Y in the upcoming election. (a) Find the sample proportion planning to vote for Candidate Y. (Round your answer to two decimal places.) (b) Calculate the standard error of the sample proportion. (Round your answer to three decimal places.) (c) Find a 95% confidence interval for the proportion of the registered voter population who plan to vote for...
In a random sample of 400 registrered voters, 120 indicated they plan to vote for Candidate A. Determine a 95% confidence interval for the proportion of all the registered voters who will vote for Candidate A.
A previous random sample of 4000 U.S. citizens yielded 2250 who are in favor of gun control legislation. How many citizens would need to be sampled for a 95% confidence interval to estimate the true proportion within 2%
a person asks a random sample of people if they will vote in an upcoming election. What type of data will this survery provide and what type of confidence interval could we create with the data? qualiataive, population mean or qualitative, population proportion
There are 20,000 eligible voters in York County, South Carolina. A random sample of 500 York County voters revealed 350 plan to vote to return Louella Miller to the state senate. a. Construct a 99% confidence interval for the proportion of voters in the county who plan to vote for Ms. Miller. (Round your answers to 3 decimal places) Confidence interval for the proportion is.............. and ...................
What percent of eligible Americans vote? In 2008, a random sample of 500 American adults was taken and we found that 68% of them voted. How many of the 500 adults in the sample voted? Now construct a 95% confidence interval estimate of the population percent of Americans that vote and write a sentence to explain the confidence interval.