Suppose that the wavenumber of the J = 1 ← 0 rotational
transition of 1H79Br considered as a rigid
rotor was measured to be 17.89 cm-1, what is
(a) the moment of inertia of the molecule? Ans = _____
kg-m2
(b) the bond length? Ans = _____ Angstroms
(Given the isotopic masses:(m(79Br) = 78.9183 amu,
m(81Br) = 80.9163 amu)
Suppose that the wavenumber of the J = 1 ← 0 rotational transition of 1H79Br considered...
Suppose the wavenumber of the fundamental vibrational transition of 79Br81Br was measured to be 363.4cm-1. Calculate the force constant of the bond in SI units given the isotopic masses:(m(79Br) = 78.9183 amu, m(81Br) = 80.9163 amu). Answer:__________________N m-1
bond length for 12C16O = 112.8 pm .t 5. Calculate the frequency of the emitted photon for the rotational J-l --,-0 transition for ICl O. Treat the molecule as a rigid rotator, using the bond length in Table 5.1. The observed frequency is 115.271208 GHz; how well do your results match this? .t 5. Calculate the frequency of the emitted photon for the rotational J-l --,-0 transition for ICl O. Treat the molecule as a rigid rotator, using the bond...
(4) Thermodynamic data suggests that copper monohalides (CuX) should exist as polymers in the gas phaso However, scientists have successfully synthesized CuX monomers and characterized them using microwave spectroscopy For Cu Br the J-13 14,J-1415 and J-1516 transitions occurred at 84421.34 MHz, 90449.25 MHz and 96476.72 MHz, respectively. Assuming Cu Br behaves as a 3D rigid rotor, answer the following questions. Note: Absorption frequency (in units of Hz) of a rotational transition (aka peak position in a microwave spectrum) corresponding...
Calculate the frequency of the J = 10 ← 9 transition in the pure rotational spectrum of 12C16O. Assume the equilibrium bond length is 109.99pm. What is the Frequency in Hz? What is the corresponding wavenumber in cm-1?
Molecular Rotations a. The wavefunction of rotations of diatomic molecules according to the rigid rotor approximation are spherical harmonics. Where have you seen spherical harmonics before? What are the quantum numbers that specify the wavefunctions for the rotational quantum states of a diatomic molecule? b. What are the gross and specific selection rules for pure rotational spectroscopy of a diatomic molecule? What region of the spectrum is used spectroscopy? What are the rotational energy levels for diatomic molecules and spherical...
The rotational constant of 12C32S2 is 0.109 cm1. 5. Determine and write an equation for the moment of inertia in terms of the C-S bond a) lengths. Calculate the bond length of the molecule (m(12C) = 12.00 amu, m32S) = 32.00 b) amu How can we measure this rotational constant b)
Give details. 4. Rotational levels of 1602 Calculate the moment of inertia of the 1"02 molecule given that its bond length is 120.8 pm and that the atomic mass of 160 is 15.9949 g/mol. a. b. Calculate the rotational constant B in cm and the energy of the first 3 rotational states in cm Infer the wavenumber of the first two rotational lines c. Sketch the rotational spectrum of 1602 4. Rotational levels of 1602 Calculate the moment of inertia...
Please Help! • If the wave number of the rotational transition / -0 → 1 of 'H'Br is 16.93 cm. a- Calculate the rotational constant B (Hz) b- Calculate the bond length of HBr (8) C- Calculate the energy of 1=5 → transition (J) d- If we deuterate HBr without affecting the bond length, what will happen to the position of the absorption peak?
3. The spacing between the J = 0 and J = 1 lines (corresponding to l = 0,1 = 1 quantum numbers) of the rotational spectrum of HI is 13.2 cm-1, which corresponds to B = AE0–1/2 = 6.6 cm-1. The principal isotope of Iodine has a mass of 127 amu. From this information, determine: (a) What is the moment of inertia of HI? (b) What is the HI bond length? (c) What is AE0_1 for deuterium iodide?
Physical Chemistry II: Show that the transition J = 0 to J = 2 is not allowed for rotational transitions in a diatomic molecule. The wave functions are the appropriate spherical harmonics YJ,m. Choose m=0. Remember that the dipole moment is a vector that can be written μ = μIi + μyJ + μ.k = μo(sin(9)ooslΦi) + sin (9)sin (Oj) + cos(9k)