Question

C++ ONLY

Write a function calculator that takes two floating numbers and one operator and prints out the answer based on arithmetic. Assume that there are no overflow, underflow and division by zero cases.

• Your function should be named calculator
• Your function takes three input parameter: two double numbers and one char operator
• Your function does not return anything
• Your function prints answer in the format specified below
• Your function should set precision point to 2

Note: You must use a switch case for this problem. if/else statements are not allowed.

The format of the output should be <number 1> <operator> <number 2> = <answer> . If an invalid operator is passed to the function, it should print "Invalid operator!"

If the function is called with (3, 7, '+') as the input argument:

3 + 7 = 11

If the function is called with (3, 7, '-') as the input argument:

3 - 7 = -4

If the function is called with (3, 7, '*') as the input argument:

3 * 7 = 21

If the function is called with (3, 7, '/') as the input argument:

3 / 7 = 0.43

If the function is called with (3, 7, '!') as the input argument:

Invalid operator!

Note: You do not need to write the main(), the include, or namespace commands, you only need to write the function definition.

For example:

Test	Result
calculator(3, -7, '+');	3 + -7 = -4

Answer 1

void calculator(double d1, double d2, char ch){
   double result;
   switch(ch){
      case '+':
         result=d1+d2;
         break;
      case '-':
         result=d1-d2;
         break;
      case '*':
         result=d1*d2;
         break;
      case '/':
         result=d1/d2;
         break;
      default:
         cout<<"Invalid operator"<<ch<<endl;
         return;
   }
   cout<<d1<<" "<<ch<<" "<<d2<<" = "<<result<<endl;
}