Question

The density of ice near 0 C. is 0.917 g/cm³. If a 35 g ice cube floats on the surface of water (1.00 g/cm³), what volume of the ice is visible above the surface?

Answer 1

Answer:

According to Buyoncy principle, the mass replace by solid in liquid is equal to the mass of solid floating.

So mass of solid floating = 35 g

and volume of 35 g of ice is = mass/density = 35 g / (0.917 g/cm³) = 38.168 cm³

density of water = 1 g/cm³    (given)

So amount of mass displace according to buyoncy law/principle = 35 g

Volume of 35 g of water = 35 cm³ (because its density is equals to 1g/cm³)

Also we can see, volume which is displacing water is not visible to us = 35 cm³

So volume visible above surface = total volume - volume not vsible = 38.168 cm³ - 35.000 cm³ = 3.168 cm³