Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean equals 137 days and standard deviation equals 12 days. The probability that a random sample of size 17 will have a mean gestation period within 12 days of the mean is ?
.
Solution :
Given that,
mean = = 137 days
standard deviation = = 12 days
n = 17
= 137 days
= / n = 12 / 17 = 2.91
137 ± 12 = 125,149
P(125 < < 149)
= P[(125 - 137) / 2.91 < ( - ) / < (149 - 137) / 2.91)]
= P( -4.12 < Z < 4.12)
= P(Z < 4.12) - P(Z < -4.12)
Using z table,
= 1 - 0
= 1
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