The rearrangement of cyclopropane to propene at 500 °C (CH2)3 CH3CH=CH2 is first order in (CH2)3 with a rate constant of 6.70×10-4 s-1. If the initial concentration of (CH2)3 is 6.15×10-2 M, the concentration of (CH2)3 will be M after 1889 s have passed.
This is what i have so far but i do not know how to cancel the ln. Teacher in class said "take e^x of both sides to cancel but did not explain this at all.
ln ((7.36x10^-2 M)/[PH3]t) = (1.8 x 10^-2 s -1)(113 s)
ln((7.36x10^-2 M)/[PH3]t) = 2.034
The rearrangement of cyclopropane to propene at 500 °C (CH2)3 CH3CH=CH2 is first order in (CH2)3...
The rearrangement of cyclopropane to propene at 500 °C (CH2)3 CH3CH=CH2 is first order in (CH2)3 with a rate constant of 6.70×10-4 s-1. If the initial concentration of (CH2)3 is 0.182 M, the concentration of (CH2)3 will be M after 1948 s have passed.
The rearrangement of cyclopropane to propene at 500 °C (CH)3 —CH,CH-CH2 is first order in (CH), with a rate constant of 6.70*10*, If the initial concentration of (CH2), is 3.68x102 Mthe concentration of (CH2), will be Mafter 3045 s have passed.
please answer the following question For the rearrangement of cyclopropane to propene at 500 °C (CH2)3—*CH3CH=CH2 the following data have been obtained: 0.132 8.25x10-2 3.23x10-2 [(CH2)3], M time, min 5.16*10-2 23.4 0 11.7 35.1 The average rate of disappearance of (CH2)3 over the time period from t= 23.4 min to t= 35.1 min is M min-1
2. At 500 °C, cyclopropane (C3H6) rearranges to propene (CH3CH=CH2): C3H6 (g) → CH3CH=CH2 (8) The reaction is first order and the rate constant is 6.7 x 10-4 5-1. (a) What is the rate law for the reaction, and; (b) if the initial concentration of C3H6 is 0.100 M, what is the concentration of cyclopropane of after 20 min?
For the isomerization of cyclopropane into propene cyclo-C3H6 ⟶ CH3CH=CH2 the rate constants of the forward and backward reactions are 1.47 × 10^13 s–1and 5.19 × 10^12 s–1respectively at a temperature of 1500 K. Determine the partial pressure of cyclopropane at equilibrium if the initial partial pressure is 0.100 bar.
At 500 ∘C, cyclopropane (C3H6) rearranges to propene (CH3−CH=CH2). The reaction is first order, and the rate constant is 6.7×10−4s−1. If the initial concentration of C3H6 is 5.50×10−2 M . What is the molarity of C3H6 after 30 min ? How many minutes does it take for the C3H6 concentration to drop to 1.00×10−2 M ? How many minutes does it take for 25% of the C3H6 to react? Express all the answers in two significant figures.
3. Upon heating, the gas cyclopropane (CH2)a undergoes isomerization to form propene (CH2CH=CH2) The rate constant for this first-order reaction is 6.7 x 10^s? If the flask is initially 0.50 M in cyclopropane with no propene present, what will be the molarity of both cyclopropane and propene after 15 minutes? How many minutes will it take for the flask to be 0.1 M in cyclopropane and 0,4 M in propene? Also, calculate the half-life of this reaction. Hint: minutes must...
At 500 ∘ C , cyclopropane ( C 3 H 6 ) rearranges to propene ( CH 3 −CH= CH 2 ). The reaction is first order, and the rate constant is 6.7× 10 −4 s −1 . If the initial concentration of C 3 H 6 is 5.50×10−2 M . Part A Part complete What is the half-life (in minutes) of this reaction? Express your answer using two significant figures. t 1/2 = 17 min SubmitPrevious Answers Correct Part...
The rate constant for the first-order isomerization of cyclopropane C3H6 to propane CH3CH=CH2 is 6.7 x 10^-4 s^-1 at 500 degrees celsius. What is its value at 300 degrees celsius? Ea=272 kj/mol^-1
The rate constant for the first-order isomerization of cyclopropane C3H6 to propane CH3CH=CH2 is 6.7 x 10^-4 s^-1 at 500 degrees celsius. What is its value at 300 degrees celsius? Ea=272 kj/mol^-1 Explain , write step by step and write every calculation made