Two parallel plates of area 170 cm2 are given charges of equal magnitudes 5.0 × 10^-7...
Two parallel plates of area 170 cm2 are given charges of equal magnitudes 5.0 × 10^-7 C but opposite signs. The electric field within the dielectric material filling the space between the plates is 1.8 × 10^6 V/m. (a) Calculate the dielectric constant of the material. (b) Determine the magnitude of the charge induced on each dielectric surface.
Homework Answers
Add Answer to:
Two parallel plates of area 170 cm2 are given charges of equal
magnitudes 5.0 × 10^-7...
Two parallel plates of area 110 cm2 are given charges of equal magnitudes 9.6 × 10-7...
Two parallel plates of area 110 cm2 are given charges of equal magnitudes 9.6 × 10-7 C but opposite signs. The electric field within the dielectric material filling the space between the plates is 1.7 × 106 V/m. (a) Calculate the dielectric constant of the material. (b) Determine the magnitude of the charge induced on each dielectric surface.
Two parallel plates of area 140 cm2 are given charges of equal magnitudes 5.0 x 107...
Two parallel plates of area 140 cm2 are given charges of equal magnitudes 5.0 x 107 C but opposite signs. The electric field within the dielectric material filling the space between the plates is 1.3 x 106 V/m. (a) Calculate the dielectric constant of the material. (b) Determine the magnitude of the charge induced on each dielectric surface. (a) Number Units (b) Number Units Click if you would like to Show Work for this question: Open Show Work
Suppose the parallel plates in Fig. 24.15 each have an area of 2000 cm2 (2.00 x 101m2) and are 1....
Suppose the parallel plates in Fig. 24.15 each have an area of 2000 cm2 (2.00 x 101m2) and are 1.00 cm (1.00 x 104m) apart, we connect the capacitor to a power supply, charge it to a potential difference V。. 3.00kv, and disconnect the power supply. We then insert a sheet of insulating plastic material between the plates, completely filling the space between them. We find that the potential difference decreases to 1.00kV while the charge on each capacitor plate...
Two parallel plates have equal and opposite charges. When the space between the plates is evacuated,...
Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E= 3.10×105 V/m . When the space is filled with dielectric, the electric field is E= 2.40×105 V/m . What is the charge density on each surface of the dielectric and the dielectric constant?
1. Two parallel plates, each of area 5.17 cm2, are separated by 4.90 mm. The space...
1. Two parallel plates, each of area 5.17 cm2, are separated by 4.90 mm. The space between the plates is filled with air. A voltage of 4.75 V is applied between the plates. Calculate the magnitude of the electric field between the plates. 2. Calculate the amount of the electric charge stored on each plate. 3. Now distilled water is placed between the plates and the capacitor is charged up again to the same voltage as before. Calculate the magnitude...
Problem 02 The parallel plates in Fig.23.9a have an area A 0.2 and separation distance d 0.01 m. ...
Problem 02 The parallel plates in Fig.23.9a have an area A 0.2 and separation distance d 0.01 m. The original potential difference between them is Δ VO-300 V which decreases to AV 100V when a dielectric sheet fills the space between the plates, see Fig.23.9b. (a) Calculate the capacitance Co, the magnitude of the charge and the magnitude of the electric field Eo. (b) Calculate the final capacitance Cand the dielectric constant k. (c) Find the magnitudes of the induced...
Two parallel plates, each of area 3.37 cm2, are separated by 4.80 mm. The space between...
Two parallel plates, each of area 3.37 cm2, are separated by 4.80 mm. The space between the plates is filled with air. A voltage of 6.25 V is applied between the plates. Calculate the magnitude of the electric field between the plates. Tries 0/20 Calculate the amount of the electric charge stored on each plate. Tries 0/20 Now distilled water is placed between the plates and the capacitor is charged up again to the same voltage as before. Calculate the...
Two parallel plates, each of area 2.32 cm2, are separated by 3.10 mm. The space between...
Two parallel plates, each of area 2.32 cm2, are separated by 3.10 mm. The space between the plates is filled with air. A voltage of 6.05 V is applied between the plates. Calculate the magnitude of the electric field between the plates. Tries 0/20 Calculate the amount of the electric charge stored on each plate. Tries 0/20 Now distilled water is placed between the plates and the capacitor is charged up again to the same voltage as before. Calculate the...
A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of...
A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of d = 2.00 mm. The capacitor is charged to a potential difference of V0 = 150 V by a battery. A dielectric sheet (κ = 3.50) of the same area but thickness ℓ = 1.00 mm is placed between the plates without disconnecting the battery. (See figure 24-18 on page 642). Determine the initial capacitance of the air-filled capacitor. Determine the charge on the...
The charge on the 4.00 cm2 area plates of an air-filled parallel plate capacitor is such...
The charge on the 4.00 cm2 area plates of an air-filled parallel plate capacitor is such that the electric field is at the breakdown value. By what factor will the maximum charge on the plates increase when polystyrene is inserted between the plates? (The dielectric strength of air is 3.00 × 106 V/m and that of polystyrene is 2.40 x 107 V/m. The dielectric constant of polystyrene is 2.56. Supporting Materials Physical Constants Additional Materials Tutorial
Two parallel plates of area 140 cm2 are given charges of equal magnitudes 5.0 x 107 C but opposite signs. The electric field within the dielectric material filling the space between the plates is 1.3 x 106 V/m. (a) Calculate the dielectric constant of the material. (b) Determine the magnitude of the charge induced on each dielectric surface. (a) Number Units (b) Number Units Click if you would like to Show Work for this question: Open Show Work
Suppose the parallel plates in Fig. 24.15 each have an area of 2000 cm2 (2.00 x 101m2) and are 1.00 cm (1.00 x 104m) apart, we connect the capacitor to a power supply, charge it to a potential difference V。. 3.00kv, and disconnect the power supply. We then insert a sheet of insulating plastic material between the plates, completely filling the space between them. We find that the potential difference decreases to 1.00kV while the charge on each capacitor plate...
Problem 02 The parallel plates in Fig.23.9a have an area A 0.2 and separation distance d 0.01 m. The original potential difference between them is Δ VO-300 V which decreases to AV 100V when a dielectric sheet fills the space between the plates, see Fig.23.9b. (a) Calculate the capacitance Co, the magnitude of the charge and the magnitude of the electric field Eo. (b) Calculate the final capacitance Cand the dielectric constant k. (c) Find the magnitudes of the induced...
The charge on the 4.00 cm2 area plates of an air-filled parallel plate capacitor is such that the electric field is at the breakdown value. By what factor will the maximum charge on the plates increase when polystyrene is inserted between the plates? (The dielectric strength of air is 3.00 × 106 V/m and that of polystyrene is 2.40 x 107 V/m. The dielectric constant of polystyrene is 2.56. Supporting Materials Physical Constants Additional Materials Tutorial
Most questions answered within 3 hours.
-
Under certain conditions, the substance ammonium
nitrate can be broken down to form dinitrogen
monoxide and...
asked 10 seconds from now -
1. A boy stands on one end of a boat, and then walks to the
other...
asked 10 minutes ago -
Casey is on trial under criminal allegations that she engaged in
fraudulent behavior at the company...
asked 15 minutes ago -
Surplus Styles is a manufacturer of hair care products,
including shampoos, conditioners, and hair gels. The...
asked 13 minutes ago -
Using an income-expenditure diagram, use the infinite line and
double-drop line tools to show the economy...
asked 21 minutes ago -
Which expression computes a pseudorandom integer between -10 and
10 using rand()
from cstdlib?
A. (rand(...
asked 28 minutes ago -
Roybus, Inc., a manufacturer of flash memory, just reported that
its main production facility in Taiwan...
asked 36 minutes ago -
Two capacitors connected in parallel produce an equivalent
capacitance of 45.0 μF but when connected in...
asked 45 minutes ago -
The differences between the two sets of dependent data are -1,
2,-,2, 2. Round to the...
asked 1 hour ago -
A χ2-curve, looking at the relationship between age and hours
spent working at an office per...
asked 1 hour ago -
The pH of a sample of water from a river is 5.0. A
sample of effluent from...
asked 2 hours ago -
At the beginning of the period, the Fabricating Department
budgeted direct labor of $136,500 and equipment...
asked 2 hours ago