A worn, poorly set-up machine is observed to produce components whose length X follows a normal distribution with mean 14 centimeters and standard deviation 3 centimeters. Calculate the probability that the length of a component lies between 19 and 21 centimeters.
Population mean, µ = 14
Population standard deviation, σ = 3
Probability that the length of a component lies between 19 and 21 centimeters =
= P(19< X <21)
= P( (19-14)/3 < (X-µ)/σ < (21-14)/3 )
= P(1.67< z < 2.33)
= P(z < 2.33) - P(z < 1.67)
Using excel function:
= NORM.S.DIST(2.33,1) - NORM.S.DIST(1.67,1)
= 0.9901 - 0.9525
= 0.0376 (or 0.0380 without rounding off the z value)
A worn, poorly set-up machine is observed to produce components whose length X follows a normal...
question no4 in detailed (U.3413) 4. A worn, poorly set-up machine is observed to produce components whose length X follows a normal distribution with mean 20 cm and variance 2.56 cm. Calculate: a) the probability that a component is at least 24 cm long; (0.0062) b) the probability that the length of a component lies between 19 and 21 cm (0.4681)
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