Use the thermodynamic data provided below to estimate the
boiling point (in K) of V. Report your answer to zero decimal
places in standard notation (i.e. 123. kJ *For numbers ending in
zero, be sure to include the decimal!*).
Substance | ΔH°f (kJ/mol) | S° (J mol-1K-1) | ||
V (l) | 17.3 | 36.1 | ||
V (g) | 515.5 | 182.3 |
Step 1:
Given:
Hof(V(l)) = 17.3 KJ/mol
Hof(V(g)) = 515.5 KJ/mol
Balanced chemical equation is:
V(l) ---> V(g)
ΔHo rxn = 1*Hof(V(g)) - 1*Hof( V(l))
ΔHo rxn = 1*(515.5) - 1*(17.3)
ΔHo rxn = 498.2 KJ
Step 2:
Given:
Sof(V(l)) = 36.1 J/mol.K
Sof(V(g)) = 182.3 J/mol.K
Balanced chemical equation is:
V(l) ---> V(g)
ΔSo rxn = 1*Sof(V(g)) - 1*Sof( V(l))
ΔSo rxn = 1*(182.3) - 1*(36.1)
ΔSo rxn = 146.2 J/K
Step 3:
Boiling is an equilibrium process and hence ΔGo = 0
ΔGo = 0.0 KJ/mol
ΔHo = 498.2 KJ/mol
ΔSo = 146.2 J/mol.K
= 0.1462 KJ/mol.K
use:
ΔGo = ΔHo - T*ΔSo
0.0 = 498.2 - T *0.1462
T = 3408. K
Answer: 3408 K
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