calculate the concentration of Co3+ om solution when 40.0 ml of 0.010 M Co(NO3)3 aq is mixed with 10.0 ml of 6.00 M NH3 aq given Co3+(aq) + 6NH3(aq) = (Co(NH3)6)3+(aq) Kf=4.5 x 10 (33)
calculate the concentration of Co3+ om solution when 40.0 ml of 0.010 M Co(NO3)3 aq is...
Calculate the equilibrium concentration of Co3+ (aq) in a solution that is initially 0.0300 M CO(NO3)2 and 0.500M NH3. The formation constant for CO(NH3)6]** (aq) is Kf= 2.3 x 1033 ICO(NL) I Costa
100.0 mL of 1.23X10-3 M Co(NO3)3 is mixed with 150.0mL of 0.22M NH3. What is the [Co+3] at equilibrium? [Kf for Co(NH3)6 +3 is 2.3 x 1033]
5. A solution is made by mixing 200.0 ml of 1.5 x 10-4 M Cu(NO3)(aq) with 250.0 ml of 0.20 M NH3(aq). Calculate the concentration of copper ion (Cu? (aq)) in the solution when it reaches equilibrium. (Kr for [Cu(NH3)4]2+ = 1.7 x 1013)
When 0.1 L of 0.0200 M Ni(NO3)2 is combined with 0.010 L 0.3 M NH3, the Ni(NH3)62+ ion forms (Kf = 2.0 × 10^8). Calculate the equilibrium concentration of Ni2+, NH3, and Ni(NH3)62+
Consider the following precipitation reaction: 2 K3PO4 (aq) + 3 Co(NO3)2 (aq) ? Co3(PO4)2 (s) + 6 KNO3 (aq) What volume of 0.222 M K3PO4 (aq) in milliliters is needed to react with 36.75 mL of 0.250 M Co(NO3)2 (aq)? NG 5 6. Consider the following precipitation reaction: 5 Fe2+(aq) + MnO4-(aq) + 8 H+(aq) ? 5 Fe3+(aq) + Mn2+(aq) + 4 H2O(l) An iron sample weighing 0.214 g is converted into Fe2+(aq) and requires 31.57 mL of MnO4-(aq) according...
4. When 5.00 mL of 0.500 M Fe (NO3)3 are mixed with 5.00 mL of 0.250 M NaSCN, the following reaction occurs: Fe3+ (aq) + SCN(aq) $ FeSCN2+(aq) At equilibrium the concentration of FeSCN2- is found to be 6.00 x 10-2 M. A. Fill in the table below with the proper numerical values. (Remember to take into account the effects of dilution when calculating the initial molarity of Fe3+ (aq) and SCN'(aq) Fes- (aq) SCN (aq) FeSCN-(aq) Initial Molarity Change...
When 20.0 mL of 0.200 M Zn(NO3)2 is added to 30.0 mL of 6.00 M NH3, the concentrationn of Zn2+ at equilibrium is 1.00 x 10-13. What should the Kf of Zn(NH3)42+ be reported as?
4- (a) Calculate the concentration of Cd2+ ion in a solution prepared by mixing 2.0 mL of 1 M CA(NO3)2 solution with 1.0 L of 4.0 M NH3 solution. [Assume that the volume does not change after the addition of 2.0 ml of 1 M Cd(NO3)2] (b) Will you be able to see Ca(OH)2(6) precipitate in the solution? (Kr for Ca(NH3)42+ = 1.0 x 107, Kb for NH3 = 1.8 x 10-5; Ksp for Ca(OH)2 = 5.9 x 10-15 Cd2+...
Will a precipitate form when 5.00mL of 1x10^-6 M Cd(NO3)2 and 7.00 mL of 2.5x10^-5 M Na2CO3 are mixed together? [ksp(CdCO3) = 2.5x10^-14] What if he above solution was made 1.5 M in NH3 (without changing volumes?) Cd2+ forms a complex ion with NH3 [kf(Cd(NH3)4) = 1.0x10^7]
if 125 mL of a solution containing 0.0400 M of Pb(NO3)2 (aq) is mixed with 75.0 mL of a solution containing 0.0200 of NaCl(aq), will there be a precipitate? PbCl3 has a Ksp value of 1.6 x 10^-5. Assume volumes are additive when mixed