Question

C++ programming:

Write a function to sum the following series:

m(i)= 1/2 + 2/3 + ... + i/i+1

         

// i is the number of item in the series

double m(int i){

}

Answer 1

#include<iostream>

float sum(int i);

using namespace std;

int main() {

int i=4;

float n = sum(i);

cout<<"Sum: "<<n;

return 0;

}

//Function for the given condition

float sum(int i){

float sum = 0;

for (int j=1; j<=i; j++){

float k = (float)j;

sum = sum+(k/(k+1));//in the first iteration it will 1/2, then it will be 1/2+2/3 and so on upto 4/5

}

return sum;

}

Output: