A poll found that 74% of a random sample of 1013 adults said that they believe...
A poll found that 74% of a random sample of 1013 adults said that they believe in ghosts. a. Determine the margin of error for a 99% confidence interval. (Round to three decimal places) E=
Homework Answers
Solution :
Given that,
n = 1013
Point estimate = sample proportion = 
= 74% = 0.74
1 -
= 1 - 0.74 = 0.26
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2
= Z0.005 = 2.576
Margin of error = E = Z
/ 2 * 
((
* (1 -
)) / n)
= 2.576 * (((0.74
* 0.26) / 1013)
E = 0.036
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